Javascript Math Functions

JQuery doesn't need to support math functions as it is an addon library for Javascript, you can still use Javascript in your JQuery code, so you can still use all the native math functions.

Examples:

Addition

var x = 1;
var y = 2;
var lol = x+y;
alert(lol);

Subtraction

var x = 10;
var y = 1;
var lol = x-y;
alert(lol);

Edit: Now we understand your question a little better...

<input type="text" id="field1" value="16" />
<input type="text" id="field2" value="25" />
<input type="text" id="field3" value="36" />

var field1Value = document.getElementById("field1").value;
var field2Value = document.getElementById("field2").value;
var field3Value = document.getElementById("field3").value;

alert(Math.sqrt(field1Value ));
alert(Math.PI * field2Value);
alert(Math.sin(field3Value));

JavaScript is the programming language, not jQuery, which is a library for web application programming written in JavaScript. To effectively use jQuery, you need to know JavaScript.

It is, however, possible to use jQuery's functionality to easily work with multiple textboxes at once:

// Set each single-line textbox's value to the square
// of its numeric value, if its value is in fact a number.
$('input:text').each(function() {
    var num = +this.value;
    if(!isNaN(num)) {
        this.value = num * num;    // or Math.pow(num, 2)
    }
});

It would be quite useful if jQuery had a reduce() function.

When dealing with lists of data, most functional languages, and indeed most traditional languages these days, have methods that perform a repetitive function over the entire list, taking each element in turn and applying a function to it.

The simplest of these is map, which jQuery implements for you. This takes a list and applies a function to each element and returns the list of results, one result per entry in the list. eg. [1,2,3] -> (map x2) -> [2,4,6].

Sometimes you want a total or collective result from a list, rather than a list of individual mappings. This is where the reduce (or fold) operation comes in. Unfortunately jQuery does not have this method available as standard, so below is a plugin for it. A reduce function takes an accumulator value and the value of the current element, and returns the modified accumulator, which will be passed on to the next call. eg. [1,2,3,4] -> (reduce + [initial:0]) -> 10 = ( ( ( (0 + 1) + 2 ) + 3 ) + 4 ) or ([1,2,3,4] -> (reduce * [initial:1]) -> 24 = ( ( ( (1 * 1) * 2 ) * 3 ) * 4 ).

(function($) {
    $.reduce = function(arr, callback, initial) {
        var accumulator = initial || 0;

        $.each(arr, function(index, value) {
            accumulator = callback(accumulator, value, index);
        });

        return accumulator;
    }
})(jQuery);

Then you can use it like this to get a sum of squares:

var answer = $.reduce($('input:text'), function(acc, elem) {
    var cVal = $(elem).val();
    return acc + cVal * cVal;
}, 0);

i was looking for a solution too , and i saw a lot of questions here that doesn't work (even this one) in case someone wondering like me , here is my working solutiuon :

$("#apport").keyup( 
function(){
var apport = parseFloat($("#apport").val());
var montant = parseFloat($("#montant-financer").val());
var moinmontant = parseFloat(montant) - parseFloat(apport);     
$("#montant-financer").val(moinmontant);    
}
);

All the id's selector are input

Use the jquery map function to create an array

$('input:text').map(function() {
  return this.value * this.value; // math calculation goes here
}).get();

See a live example

Looking at the initial question that was posted, it clearly states compute the square of all values in a form, without submiting the form.

i think keyup would be the best solution.

$("input").keyup(function () {
  var value = $(this).val();
  var x=value*value;
  $("p").text(x);
}).keyup();

Click here to check the working example. http://jsfiddle.net/informativejavascript/Sfdsj/3/

For more details visit http://informativejavascript.blogspot.nl/