Java8 Lambda function - adding new parameter

Question

I have following code :

categoryList = Prices.stream()
               .filter(price -> price.getPrice() != null)
               .map(this::createCategory)
               .filter(Objects::nonNull)
               .collect(Collectors.toList());

And the method looks like :

private Category createCategory(PriceCategory price) {
        Category category = new Category();
        category.setId(price.getId());
        return category;
    }

I want to add a new parameter to the method createCategory - like createCategory(PriceCategory price, response) But I don't have idea about setting this new parameter in the lambda function. Can anyone please help in this

You are using a method reference. Just change it to a lambda expression and the problem disappears (hint: a lambda expression is what you are using in the preceding filter step). — Holger
– Holger, Commented Nov 7, 2017 at 9:51
Possible but you need to define first where responses values will come from. — Jean-Baptiste Yunès
– Jean-Baptiste Yunès, Commented Nov 7, 2017 at 10:45

Eugene · Accepted Answer · 2017-11-07 09:51:58Z

3

can't you simply create a lambda instead?

.map(x -> createCategory(x, response))

answered Nov 7, 2017 at 9:51

Eugene

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1 Comment

Jean-Baptiste Yunès Over a year ago

Only in the case response value is defined in the closure.

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