Java - regex parse string

Question

Trying to parse out names with given samples

++++++++++++++++++SELIZABETH+COLLAZO+++++++++++++++++++
+++++++++++++++++++PALOMA+CORREA+++++++++++++++++++++++
+++++++++++++++++++NOAH+BLAKEMORE++++++++++++++++++++++

I've tried

//++(.*?)+(.*?)//++

but that's way off.

Would like to parse out the first and last name to two strings.

Did you mean to escape the + with \\ instead of using //, and also to escape the one in the middle? — Bernhard Barker
– Bernhard Barker, Commented Nov 7, 2017 at 15:07
To match a literal +, you should escape it with \\ in the Java string literal — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Nov 7, 2017 at 15:09

Youcef LAIDANI · Accepted Answer · 2017-11-07 15:09:10Z

5

You can use this regex (\w+)\+(\w+) or \+{2,}(.*?)\+(.*?)\+{2,} with Pattern like this :

String str = "++++++++++++++++++SELIZABETH+COLLAZO+++++++++++++++++++\n"
        + "+++++++++++++++++++PALOMA+CORREA+++++++++++++++++++++++\n"
        + "+++++++++++++++++++NOAH+BLAKEMORE++++++++++++++++++++++";

Pattern pattern = Pattern.compile("(\\w+)\\+(\\w+)");// or instead "\\+{2,}(.*?)\\+"(.*?)\\+{2,}
Matcher matcher = pattern.matcher(str);

while (matcher.find()) {
    System.out.println(matcher.group(1) + " " + matcher.group(2));
}

Outputs

SELIZABETH COLLAZO
PALOMA CORREA
NOAH BLAKEMORE

answered Nov 7, 2017 at 15:09

Youcef LAIDANI

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1 Comment

Youcef LAIDANI Over a year ago

Hi down-voter, please put a comment when you down-vote a post, it is not legal to down-vote just like this, you have to respect the efforts of others, because we respect your efforts also. Thank you.

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