Parsing local xml file in android

Question

Hii every one, am brand new to android,i have a doubt can any one help me

In this following link

http://www.androidpeople.com/android-xml-parsing-tutorial-using-saxparser/

there is a sax parser in which xml file is taken from the internet, using a URL path How to change that url to local path in which xml is stored in raw folder of the project,,can any one give me the syntax ,,thanx in advance

springrolls · Accepted Answer · 2011-01-18 13:30:44Z

3

This is what I did,

InputStream is = res.openRawResource(R.raw.fileName);
xr.parse(new InputSource(is));

answered Jan 18, 2011 at 13:30

springrolls

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7 Comments

Sowmya Over a year ago

thanx for ur reply theresia, but wat is "res"? am getting error res not declared,have u tried for that proj which is in that link,is that executing?

springrolls Over a year ago

Resource res = getResources(); Your class has to extend Activity, or at least get access to it. Pass it as a parameter, if you put your code in another class that doesn't extend Activity. I haven't tried the IBM tutorial, but I take some essential code from there. It should work for you, too.

Sowmya Over a year ago

thank u,,,,can u please give me zip file of parsing local xml (with repitative tags) sample project

springrolls Over a year ago

do you have any other problems with the repetitive tags? you can always ask. and i thought i read one post about the same question here. good luck!

Sowmya Over a year ago

no still am unable to do that,,if u hav any example please ill give me

|

Pedro Loureiro · Accepted Answer · 2011-01-18 12:09:54Z

1

In the link you provided, replace the line 47

xr.parse(new InputSource(sourceUrl.openStream()));

with

xr.parse(getResources().getAssets().open(fileName));

and place your xml file in /res/raw folder

links: Asset Manager Docs and Resources Manager Docs

answered Jan 18, 2011 at 12:09

Pedro Loureiro

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Comments

iAndroid · Accepted Answer · 2012-08-01 08:59:45Z

1

try {
//          InputStream is = getResources().getAssets().open("yourfilename.xml");
            InputStream is =getAssets().open("yourfilename.xml");
            SAXParserFactory spf = SAXParserFactory.newInstance();
            SAXParser sp = spf.newSAXParser();
            XMLReader xr = sp.getXMLReader();

            MyXMLHandler myXMLHandler = new MyXMLHandler();
            xr.setContentHandler(myXMLHandler);

            xr.parse(new InputSource(is));

        } catch (Exception e) {
            System.out.println("XML Pasing Excpetion = " + e);
        }

answered Aug 1, 2012 at 8:59

iAndroid

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Comments

Jonathan Roth · Accepted Answer · 2011-01-18 11:58:44Z

0

In Android you can store data in the assets folder, which can be entered by your code. To address your file use

file:///android_asset/yourFile.xml

I haven´t tried this yet, but I hope it will work

answered Jan 18, 2011 at 11:58

Jonathan Roth

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