Sending array with objects throw ajax to php

Question

Help me please: I create my object:

var data = [];

$("#report-container [id^='report-']").each(function(index) {
    var reportObject = {
        "subject" : "",
        "photo" : "",
        "rating" : "",
        "comment" : ""
    };
    reportObject.subject = $("#name-report-"+index).text();
    reportObject.photo = $("input[name='subject-photo-"+index+"']")[0].files[0];
    reportObject.rating = $("input[name='subject-rating-"+index+"']").val();
    reportObject.comment = $("textarea[name='subject-comment-"+index+"']").val();
    data.push(reportObject);
});

After this I have an array. I convert it to json like this:

var myarray = JSON.stringify(data);

if I console log it, it looks like this:

[{"subject":"Окна","rating":"0","comment":""},{"subject":"Пол","rating":"0","comment":""}]

And then I send it to php:

$.ajax({
    type: "POST",
    url: "/report-data/add_report.php",
    data: { data: myarray },
    async: true,
    cache: false,

and in php I try to get it like this:

$data = json_decode($_POST["data"]);
echo(json_encode("this".$data));

And it doesn't works...

put a success and an error function in the ajax callback and see which 1 is hit and also please show the error messages from the network tab — Dhaval Chheda
– Dhaval Chheda, Commented Nov 11, 2017 at 13:31
echo(json_encode("this".$data)); looks weird. What are you trying to accomplish there? — M. Eriksson
– M. Eriksson, Commented Nov 11, 2017 at 13:33
Then you should just do a var_dump($_POST) and check the real response in the dev consoles network tab. You're actually changing the data with that json_encode() (since you're adding things to it). — M. Eriksson
– M. Eriksson, Commented Nov 11, 2017 at 13:36

G.Abdessalem · Accepted Answer · 2017-11-11 14:04:35Z

1

If you try this code you will find that your php variable $data is an array()

$data = json_decode($_POST["data"]);
var_dump($data);

Then in the seconde line you have

echo(json_encode("this".$data));

whiche caused the error beacuase you can not concatenate string with an array "this".$data So try this simple changes.

echo("this".json_encode($data));

because json_encode($data) return a string than you can concatenate it with "this" wich is string

answered Nov 11, 2017 at 14:04

G.Abdessalem

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