Return list with n'th values of a list of lists - Python

Question

This is my first question here. I just started coding in Python, and trying to finish an assignment for my study in Python (it is actually supposed to be made in STATA but I want to learn Python).

So I want to do the following (note that the final_list consists of 15000 rows, this is just a small example):

final_list = [[2.0, 1.0, 5.0, 11.0, 50612.0, 0.38875884563387036, 0.5924978852272034, 8.400468826293945, 516.0, 0.0, 0.0, 0.0, 2003.0], [2.0, 1.0, 5.0, 11.0, 50612.0, 0.38875884563387036, 0.5924978852272034, 8.400468826293945, 517.0, 0.0, 0.0, 0.0, 2003.0], [2.0, 1.0, 5.0, 11.0, 50612.0, 0.38875884563387036, 0.5924978852272034, 8.400468826293945, 518.0, 0.0, 0.0, 0.0, 2003.0]

to

treshold = [11.0, 11.0, 11.0]

Now what I've tried is this:

treshold = []
for sublist in final_list:
    treshold_lst = sublist[3]
    treshold.append(treshold_lst)
print(treshold)

I receive the following error:

IndexError: list index out of range

Does anyone see what I'm doing wrong?

I don't see any error in your code repl.it/repls/OilyResponsibleBaboon — akash karothiya
– akash karothiya, Commented Nov 14, 2017 at 9:25
The final_list you've posted now is invalid. The problem obviously lies with that list, not with the logic you've posted. — khelwood
– khelwood, Commented Nov 14, 2017 at 9:30

SKN · Accepted Answer · 2017-11-14 09:30:30Z

2

Try list comprehension:

final_list = [[1,2,3,4],[1,2,3,5],[1,3,4,6]]
treshold = [sub[-1] for sub in final_list]

answered Nov 14, 2017 at 9:30

SKN

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