I am new to kotlin, I have tried several ways to use following code
val strAction = "Grid"
when(strAction){
strAction.contains("Grid")->println("position is 1")
}
In above code strAction.contains("Grid") this line is showing me an error that Incompatible Type
You can also combine when and with to get a nice syntax:
with(strAction) {
when {
contains("Grid") -> println("position is 1")
contains("bar") -> println("foo")
startsWith("foo") -> println("bar")
else -> println("foobar")
}
}
You can also save the result of when into a property:
val result = with(strAction) {
when {
contains("bar") -> "foo"
startsWith("foo") -> "bar"
else -> "foobar"
}
}
println(result)
Try this remove when(strAction) parameter from when
val strAction = "Grid"
when {
strAction.contains("Grid") -> println("position is 1")
}
strAction from when no need to pass thatYou don't need to pass strAction
val strAction = "Grid"
when {
strAction.contains("Grid") -> println("position is 1")
}
}
If there's only one case in your when, I'd recommend to use if instead. That's already what you're trying to do there:
val strAction = "Grid"
if (strAction.contains("Grid")) {
println("position is 1")
}
Even shorter, isn't it?
Just for the record: You switch on a String (in when) but have Boolean cases, which won't work. What would do the trick, though:
val strAction = "Grid"
when (strAction.contains("Grid")) {
true->println("position is 1")
}
But again, do if.
You can use Kotlin in
if ("Grid" in strAction) { println("position is 1") }
The other answers explain how to fix the problem but not what the problem actually is. Your code calculates strAction.contains("Grid") (which will be a Boolean) and then compares strAction with this value. I.e. it's equivalent to
if (strAction == strAction.contains("Grid")) {
println("position is 1")
}
They can't be equal because the types are incompatible, so this branch could never be taken and the compiler tells you this.
val strAction = "Grid"
when(strAction) {
in "Grid" -> println("position is 1")
}
