python return dictionary from function

Question

I tried a lot however still have a problem with returning dictionaries from a function. I can e.g print d1 and d2 from inside the function but not outside. When I use the following script I get: NameError: name 'd1' is not defined. Thank you for your help!

ref = """text a"""

target = """text b"""

def text_to_dict(x):
    # value formatting to list = new_values
    # key formatting to list = keys
    # dict creation from keys and new_values
    if x == ref:
        d1 = dict(zip(keys, new_values))
        return d1
    elif x == target:
        d2 = dict(zip(keys, new_values))
        return d2

text_to_dict(ref)

text_to_dict(target)

print(d1)

print(d2)

Hao XU · Accepted Answer · 2017-12-01 13:56:01Z

1

d1 and d2 are function variables, they are not visible outside the function.

dict1 = text_to_dict(ref)

dict2 = text_to_dict(target)

print(dict1)

print(dict2)

answered Dec 1, 2017 at 13:56

Hao XU

3521 silver badge11 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

python return dictionary from function

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related