Replace text within variable in Bash

Question

I am saving a Curl response into a variable here:

results=$(curl -username:password "URL/api/search/dates?dateFields=created&from=${Three_Months_Ago}&today&repos=generic-sgca" | jq -r '.results[].uri')
echo "$results"

which returns the following:

URL/api/storage/generic-sgca/Lastest_Deploy.tar
URL/api/storage/generic-sgca/Installer-Deploy-0.0.5/SignalStudioPro-Alpha-1-linux-x64-installer.run
URL/api/storage/generic-sgca/Installer-Deploy-0.0.5/SignalStudioPro-Alpha-1-windows-installer.exe
URL/api/storage/generic-sgca/Installer-Deploy-0.0.99/SignalStudioPro-Alpha-1-linux-x64-installer.run
URL/api/storage/generic-sgca/Installer-Deploy-0.0.99/SignalStudioPro-Alpha-1-windows-installer.exe
URL/api/storage/generic-sgca/Installer-Deploy-0.2.0/SignalStudioPro-Alpha-2-linux-x64-installer.run
URL/api/storage/generic-sgca/Installer-Deploy-0.2.0/SignalStudioPro-Alpha-2-windows-installer.exe
URL/api/storage/generic-sgca/Installer-Deploy-100.0.0/SignalStudioPro-Alpha-2-linux-x64-installer.run
URL/api/storage/generic-sgca/Installer-Deploy-100.0.0/SignalStudioPro-Alpha-2-windows-installer.exe
URL/api/storage/generic-sgca/Installer-Deploy-101.0.0/SignalStudioPro-Alpha-2-linux-x64-installer.run
URL/api/storage/generic-sgca/Installer-Deploy-101.0.0/SignalStudioPro-Alpha-2-windows-installer.exe
URL/api/storage/generic-sgca/Installer-Deploy-99.9.9/SignalStudioPro-Alpha-2-linux-x64-installer.run
URL/api/storage/generic-sgca/Installer-Deploy-99.9.9/SignalStudioPro-Alpha-2-windows-installer.exe
URL/api/storage/generic-sgca/Installer-Deploy-99.9.91/SignalStudioPro-Alpha-2-linux-x64-installer.run
URL/api/storage/generic-sgca/Installer-Deploy-99.9.91/SignalStudioPro-Alpha-2-windows-installer.exe

In each of these lines, I need to remove the "/api/storage" part of the URL. How can I accomplish this?

The simple answer is: don't store a multiline response in a single variable; see Bash FAQ 001 as I mentioned your previous question. — chepner
– chepner, Commented Dec 4, 2017 at 18:49

tripleee · Accepted Answer · 2017-12-04 18:12:20Z

1

echo "${results//\/api\/storage/}"

would do what you're asking, but there is probably no good reason to capture the result in a variable just to print it. Maybe you're better off with

curl ... | jq ... | sed 's=/api/storage=='

or figuring out how to do the subsititution as part of your jq script.

answered Dec 4, 2017 at 18:12

tripleee

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1 Comment

VivaLaRobo Over a year ago

I was able to get it with adding the |sed 's=/api/storage==' to the end of my curl command. I think I got it working now, thank you very much.

Benjamin W. · Accepted Answer · 2017-12-04 18:08:37Z

1

With parameter expansion:

echo "${results//\/api\/storage}"

answered Dec 4, 2017 at 18:08

Benjamin W.

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