Converting PHP array to a single JSON object using js

Question

I have a php array(zero indexed) which I am sending to front end directly by echoing its json_encode format.

I want the JSON object to look like

{
    'A': null,
    'B': null,
    'C': null
}

But when I tried console.log i.e.,

console.log(<?php echo json_encode($array); ?>)

its printing js array

Also when I try print_r($array) in backend it prints

[array] => Array
    (
        [0] => A
        [1] => B
        [2] => C

    )

Thanks in advance

Well that isn't a zero indexed array, it's an associative array. So I'm guessing what you actually have is a multidimensional zero indexed array which is filled with associative arrays, and you are outputting the whole thing. — miknik
– miknik, Commented Dec 5, 2017 at 17:55
Without some sort of transformation of the array on the backend, you'll never get what you are expecting. The code that creates the PHP array must be modified. — Brian Gottier
– Brian Gottier, Commented Dec 5, 2017 at 18:12

Ravinder Reddy · Accepted Answer · 2017-12-05 18:39:49Z

3

This code gives you the desired out put

$array = array
    (
        '0' => 'A',
        '1' => 'B',
        '2' => 'C'

    );
    $array = array_fill_keys($array, NULL);

echo json_encode($array);

Out Put:

{"A":null,"B":null,"C":null}

Javascript:

<script type="text/javascript">
<!--
var data =<?php echo json_encode($array); ?>;

console.log(data);
//-->
</script>

Out Put:

 Object {A: null, B: null, C: null}
    A:null
    B:null
    C:null

edited Dec 5, 2017 at 18:39

answered Dec 5, 2017 at 18:16

Ravinder Reddy

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Comments

Bobby Dawson · Accepted Answer · 2017-12-05 18:11:56Z

2

Why not just make your PHP array an array of ['A' => null, 'B' => null...]

Otherwise, your other option would be:

   $newArray = array_fill_keys($tags, null);
   json_encode($newArray);

This would take each array element in $tags, and set it as your index in newArray with a value of null.

Based on your code, you would have:

<?php $newArray = array_fill_keys($tags, null);
$json = json_encode($newArray); ?>
console.log(JSON.parse(<?= $json; ?>));

edited Dec 5, 2017 at 18:11

answered Dec 5, 2017 at 17:41

Bobby Dawson

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2 Comments

pokemon Over a year ago

Thats showing Uncaught SyntaxError: Unexpected token , in JSON at position 0 at JSON.parse (<anonymous>) at HTMLDocument.<anonymous> (question:533) at j (jquery.min.js:2) at k (jquery.min.js:2)

Bobby Dawson Over a year ago

My mistake @pokemon, I misstyped based on reading your post. try my edit. You do not need "array_keys" - using my exact code, I was able to get what you are looking for.

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