Searching array for multiple value

Question

I've got an array containing

"1", "2", "3", "4"

And I use array_rand to select one of those numbers randomly five times. Then I want to count how many of the result of array_rand that have been chosen multiple times like the number 2 got chosen 2 times and number 3 got chosen 2 times.

I have tested doing this

$array = array($kort1[$rand_kort1[0]], $kort1[$rand_kort2[0]], $kort1[$rand_kort3[0]], $kort1[$rand_kort4[0]], $kort1[$rand_kort5[0]]);
$bank = array_count_values($array);
if (in_array("2", $bank)) {
    echo "You got one pair";
} elseif(in_array("2", $bank) && (???)) {
    echo "You got two pair";
}

it will tell me "You got one pair" if one of those numbers were randomly chosen 2 times but my problem is I don't know how to make it say "You got two pairs" if 2 of those numbers were chosen 2 times. the result of $bank could be

 [4] => 1 [3] => 2 [1] => 2

@Erwin [3] => 2 [1] => 2 thats two pairs and the code should ignore the last number — Patric Nøis
– Patric Nøis, Commented Dec 8, 2017 at 3:24
How bout four of a kind? Is that also considered two pairs? e.g. [3] => 4 [1] => 1 — Goma
– Goma, Commented Dec 8, 2017 at 3:27

Community · Accepted Answer · 2023-11-17 19:37:06Z

1

Try this: (This will work even if your array has more than 4 values)

$count = 0;
foreach ($bank as $key=>$value) {
    if ($value === 2) {
        $count++;
    }
}

if ($count) {
    $s = $count > 1 ? 's' : '';
    echo "You got $count pair$s";
}

It will show an output like You got 1 pair. If you want to use words (like you mentioned in your question), you can use NumberFormatter class

edited Nov 17, 2023 at 19:37

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answered Dec 8, 2017 at 3:27

Kamrul Khan

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Comments

miknik · Accepted Answer · 2017-12-08 22:14:21Z

1

You can use array_filter to appy a function to each element of your array

$bank=array(4 => 1, 3 => 2, 1 => 2); // Your array
function pairs($var) {
    return($var === 2); // returns value if the input integer equals 2
} 
$pairs=count(array_filter($bank, "pairs")); // Apply the function to all elements of the array and get the number of times 2 was found
if ($pairs === 1)  
{
echo "you got one pair";
}
if ($pairs === 2) {
echo "you got two pairs";
}

EDIT

Thought of this one liner later:

$pairs=count(array_diff($bank, array(1,3,4)));

edited Dec 8, 2017 at 22:14

answered Dec 8, 2017 at 3:26

miknik

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