Converting Pandas DataFrame to tkinter object

I think pandas can't use StringVar as dtype.

You would have to get every element in dataframe and create separated var = StringVar(value=df[row,col]) (or var = StringVar() ; var.set(df[row,col]))) and keep them in standard list.

But you could put values directly to Entry, and bind() event to Entry which will execute function everytime something change in Entry or you press Enter. This function could copy value from Entry to dataframe.

EDIT: example code

It changes value in dataframe when you click Enter (or Enter on keypad) in any Entry.

import pandas as pd
import tkinter as tk

df = pd.DataFrame([[1,2,3], [5,6,7], [101,102,103]])

# --- functions ---

def change(event, row, col):
    # get value from Entry
    value = event.widget.get()
    # set value in dataframe
    df.iloc[row,col] = value
    print(df)

# --- main --    

root = tk.Tk()

# create entry for every element in dataframe

rows, cols = df.shape

for r in range(rows):
    for c in range(cols):
        e = tk.Entry(root)
        e.insert(0, df.iloc[r,c])
        e.grid(row=r, column=c)
        # ENTER 
        e.bind('<Return>', lambda event, y=r, x=c: change(event,y,x))
        # ENTER on keypad
        e.bind('<KP_Enter>', lambda event, y=r, x=c: change(event,y,x))

# start program

root.mainloop()

To change value in dataframe with every key press use <KeyRelease>

(it works when you press Ctrl+V too, so you can paste data from clipboard)

for r in range(rows):
    for c in range(cols):
        e = tk.Entry(root)
        e.insert(0, df.iloc[r,c])
        e.grid(row=r, column=c)
        e.bind('<KeyRelease>', lambda event, y=r, x=c: changed(event, y,x))

EDIT: example as class DataFrameEdit(tk.Frame)