How do I insert space when text changed from numeric input to alphabetic input and vice-versa?

Question

Here is what I'm trying to do. I need to add a space between a numeric input and an alphabet input. I'm using the TextWatcher class but I could no get what exactly I want

if the input text is:

APyt04XC2446

I need it as

APyt 04 XC 2446

but i'm getting this:

APyt 0 4 X C 2 4 4 6

This is my TextWatcher class:

public class FormattingTextWatcher implements TextWatcher {

private static final String EMPTY_STRING = "";
private static final String WHITE_SPACE = " ";
private String lastSource = EMPTY_STRING;

@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {


}

@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}

@Override
public void afterTextChanged(Editable s) {
    String source = s.toString();

    if (!lastSource.equals(source)) {
        source = source.replace(WHITE_SPACE, EMPTY_STRING);
        StringBuilder stringBuilder = new StringBuilder();
        for (int i = 0; i < source.length(); i++) {
            if ((s.charAt(i)>='a' && s.charAt(i)<='z') || (s.charAt(i)>='A' && s.charAt(i)<='Z')) {
            } else {
                stringBuilder.append(WHITE_SPACE);
            }
            stringBuilder.append(source.charAt(i));
        }
        lastSource = stringBuilder.toString();
        s.replace(0, s.length(), lastSource);
    }
} }

kindly get me out of this... thanks

Possible duplicate of How to add spaces between number and word in a string in Java? — SpiritCrusher
– SpiritCrusher, Commented Dec 11, 2017 at 6:56

R.R.M · Accepted Answer · 2017-12-11 07:00:20Z

0

Try this:

public class FormattingTextWatcher implements TextWatcher {

private static final String EMPTY_STRING = "";
private static final String WHITE_SPACE = " ";
private String lastSource = EMPTY_STRING;

@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {


}

@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}

@Override
public void afterTextChanged(Editable s) {
    String source = s.toString();

    int letterFlag = -1;

    if(Character.isLetter(character.charAt(0)){
       letterFlag = 0;
    }
    else{
       letterFlag = 1;
    }       

    for (int i = 1; i < source.length(); i++) {

          if(letterFlag == 1){
                if(Character.isLetter(character.charAt(i)){
                    stringBuilder.append(WHITE_SPACE);
                    letterFlag = 0;
                }
          }
          else{
               if(Character.isDigit(character.charAt(i)){
                    stringBuilder.append(WHITE_SPACE);
                    letterFlag = 1;
               }
          }

          stringBuilder.append(source.charAt(i));

   }


} }

answered Dec 11, 2017 at 7:00

R.R.M

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2 Comments

Darshuu Over a year ago

what is character keyword initialization here

R.R.M Over a year ago

Just import it. It is class present in android studio, use alt+enter to import it.

Saif Ahmad · Accepted Answer · 2017-12-11 07:38:44Z

0

For you

public class FormattingTextWatcher implements TextWatcher {

private static final String EMPTY_STRING = "";
private static final String WHITE_SPACE = " ";
private String lastSource = EMPTY_STRING;

@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {


}

@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}

@Override
public void afterTextChanged(Editable s) {
    String source = s.toString();

    if (!lastSource.equals(source)) {
        source = source.replace(WHITE_SPACE, EMPTY_STRING);
        StringBuilder stringBuilder = new StringBuilder();
        if ((str.charAt(0) >= 'a' && str.charAt(0) <= 'z') || (str.charAt(0) >= 'A' && str.charAt(0) <= 'Z'))
            flag = 1;
        else if ((str.charAt(0) >= '0' && str.charAt(0) <= '9'))
            flag = 0;
        for (int i = 0; i < str.length(); i++) {
            if (((str.charAt(i) >= 'a' && str.charAt(i) <= 'z') || (str.charAt(i) >= 'A' && str.charAt(i) <= 'Z')) && flag == 0) {
                stringBuilder.append(WHITE_SPACE);
                stringBuilder.append(str.charAt(i));
                flag = 1;
                continue;
            } else if ((str.charAt(i) >= '0' && str.charAt(i) <= '9') && flag == 1) {
                stringBuilder.append(WHITE_SPACE);
                stringBuilder.append(str.charAt(i));
                flag = 0;
                continue;
            }
            stringBuilder.append(str.charAt(i));
        }
        lastSource = stringBuilder.toString();
        lastSource = lastSource.replaceAll("\\s+", " "); // it would remove the extra spaces between characters
        s.replace(0, s.length(), lastSource);
    }
}
}

edited Dec 11, 2017 at 7:38

answered Dec 11, 2017 at 7:01

Saif Ahmad

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4 Comments

Darshuu Over a year ago

is adding space to the previous separation too..like this APyt 04 XC 2442. the space between apty and 04 is continuously increasing

Saif Ahmad Over a year ago

@Darshuu Fixed the issue you had. Answer Updated

Darshuu Over a year ago

fixed the spacing issue...but here comes another issue when i press backspace in keypad it's add some garbage alphabets instead of deleting the last entered charater...this is only while removing alphabets but in case of letters it works fine

Darshuu Over a year ago

here is the thing happenning its showing as AP 31 gfffffgggfgfdfggs 5643...when i used back press for the 3 rd word

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