JSON parse string? [duplicate]

Question

I have a JSON file that contains two objects. This file is in server side.

[ {"param1":"market"}, {"param2":"you"} ]

I want to parse these objects and set to my String param1,param2

private String param1 = null;
private String param2 = null;

I can not understand how to code. Please give me sample code for this.

@Dalton I did not know how to parse. The link you wrote who asked that question said " I have already got JSON string by code " — jancooth
– jancooth, Commented Dec 11, 2017 at 18:30

Anchal Singh · Accepted Answer · 2017-12-11 18:23:27Z

0

[ {"param1":"market"}, {"param2":"you"} ]

The square brackets are showing that your response starts with JSON array. So, you should have key name of JSON array so that you can find the value of JSON objects from JSON array.

answered Dec 11, 2017 at 18:23

Anchal Singh

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2 Comments

jancooth Over a year ago

Can you give me sample code ? I am newbie development of android.

Anchal Singh Over a year ago

JSON Parsing Tutorial, hope this will help you.

Soon Santos · Accepted Answer · 2017-12-11 19:02:48Z

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String string = "[ {"param1":"market"}, {"param2":"you"} ]"

JSONArray arr = new JSONArray(string);

JSONObject firstPart = arr.getJSONObject(0);

JSONObject secondPart = arr.getJSONObject(1);

firstPart.getString("param1");
secondPart.getString("param2");

answered Dec 11, 2017 at 19:02

Soon Santos

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2 Comments

jancooth Over a year ago

my objects are in server side. I keep it in txt file. Can you modify your code ?

Soon Santos Over a year ago

This code seems to be a string or already an JSONArray, if it is the first, do it like the code I wrote. If it is the second case you just delete the first two lines.

Mark Samy · Accepted Answer · 2017-12-11 21:50:16Z

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so you need to call the server to get the jsonString you can make service call like this by passing url and getting the json str

public String makeServiceCall(String reqUrl) {
        String response = null;
        try {
            URL url = new URL(reqUrl);
            HttpURLConnection conn = (HttpURLConnection) url.openConnection();
            conn.setRequestMethod("GET");
            InputStream in = new BufferedInputStream(conn.getInputStream());
            response = convertStreamToString(in);
        } catch (MalformedURLException e) {
            Log.e(TAG, "MalformedURLException: " + e.getMessage());
        } catch (ProtocolException e) {
            Log.e(TAG, "ProtocolException: " + e.getMessage());
        } catch (IOException e) {
            Log.e(TAG, "IOException: " + e.getMessage());
        } catch (Exception e) {
            Log.e(TAG, "Exception: " + e.getMessage());
        }
        return response;
    }

then you use the jsonStr you get from the call like this.

String jsonStr = makeServiceCall(String reqUrl);
JSONArray jsonArr= new JSONArray(jsonStr);
JSONObject jsonObjectOne = jsonArr.getJSONObject(0);
String param1 = jsonObjectOne.getString("param1");
JSONObject jsonObjectTwo = jsonArr.getJSONObject(1);
String param2 = jsonObjectTwo.getString("param2");

edited Dec 11, 2017 at 21:50

answered Dec 11, 2017 at 18:48

Mark Samy

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2 Comments

jancooth Over a year ago

jsonStr is in server side. I keep it in txt file. Can you modify your code ?

Mark Samy Over a year ago

Edited the answer hope it can help.

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