How to replace a string by using UNIX command?

Question

How to replace a string by number of times other/itself string?

e.g. UNIX is good. replace UNIX by 4 times O/p : UNIXUNIXUNIXUNIX is good.

How to do similar way n times?.

ctac_ · Accepted Answer · 2017-12-12 19:40:47Z

1

This one is good too

echo 'UNIX is good.' | sed 's/[^ ]*/&&&&/'

answered Dec 12, 2017 at 19:40

ctac_

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1 Comment

If it's for n times? Instead just 4 times.

John1024 · Accepted Answer · 2017-12-12 17:52:37Z

0

With this test file:

$ cat File
UNIX is good.

Try:

$ awk -v n=4 '{for (i=1;i<n;i++)sub(/(UNIX)+/, "&UNIX")} 1' File
UNIXUNIXUNIXUNIX is good.

Or:

$ s='UNIX is good.'
$ n=4; for ((i=1;i<n;i++)); do s=${s/UNIX/UNIXUNIX}; done; echo "$s"
UNIXUNIXUNIXUNIX is good.

answered Dec 12, 2017 at 17:52

John1024

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GAD3R · Accepted Answer · 2017-12-15 12:34:01Z

0

a perl script:

#!/usr/local/bin/perl
use strict;
use warnings;
my $n= 4;
print 'UNIX'x$n . ' is good';

answered Dec 15, 2017 at 12:34

GAD3R

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