If I had an array such as:
testarray = array('foo'=>34, 'bar'=>array(1, 2, 3));
How would I go about converting a string such as testarray[bar][0] to find the value its describing?
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1look on eval php.net/manual/en/function.eval.phpHaim Evgi– Haim Evgi2011-01-24 13:15:13 +00:00Commented Jan 24, 2011 at 13:15
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3What are you trying to do? There may be better ways to do thisPekka– Pekka2011-01-24 13:15:14 +00:00Commented Jan 24, 2011 at 13:15
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1I agree with @Pekka -- I can't imagine a use-case for this that would be considered good practice.Spudley– Spudley2011-01-24 13:19:49 +00:00Commented Jan 24, 2011 at 13:19
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I have a function that takes a parameter of a $_POST value and validates it, however it won't work with field values that are arrays, because $_POST['testfield[0][foo]'] != $_POST[testfield][0][foo]Richard Carter– Richard Carter2011-01-24 13:31:15 +00:00Commented Jan 24, 2011 at 13:31
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You may want to prepend a $ to you variable name.Geoffrey– Geoffrey2011-01-24 14:09:38 +00:00Commented Jan 24, 2011 at 14:09
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2 Answers
Well, you can do something like this (Not the prettiest, but far safer than eval)...:
$string = "testarray[bar][0]";
$variableBlock = '[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*';
$regex = '/^('.$variableBlock.')((\[\w+\])*)$/';
if (preg_match($regex, $string, $match)) {
$variableName = $match[1]; // "testarray"
if (!isset($$variableName)) {
//Error, the variable does not exist
return null;
} else {
$array = $$variableName;
if (preg_match_all('/\[(\w+)\]/', $match[2], $matches)) {
foreach ($matches[1] as $match) {
if (!is_array($array)) {
$array = null;
break;
}
$array = isset($array[$match]) ? $array[$match] : null;
}
}
return $array;
}
} else {
//error, not in correct format
}
1 Comment
Your Common Sense
while the OP can achieve his goal by just calling
check_post(&$_POST[testfield][0][foo]);You could use PHP's eval function.
http://php.net/manual/en/function.eval.php
However, make absolutely sure the input is sanitized!
Cheers
