how to generate a matrix of random integers without duplicates in python

Question

i need some help to create a matrix of dim (65, 8) where all elements are unique integers in range(522) in python

thanx!!

def bootstrap(x, num_samples, statistic, alpha):
"""Returns bootstrap estimate of 100.0*(1-alpha) CI for statistic."""
n = len(x)
y=len(x)**(1/3)
idx = np.random.randint(0, n, (num_samples, y)) #Return unique random integers from 0 to 520 in a martix with size num_samples X 520.
samples = x[idx]
stat = np.sort(statistic(samples, 1))
return (stat[int((alpha/2.0)*num_samples)],
        stat[int((1-alpha/2.0)*num_samples)])

Why it should be from range 0 to 521? This matrix should have exactly 520 elements. So do you want two of them to be missing? — running.t
– running.t, Commented Dec 15, 2017 at 8:47
Including 0? So do you want numbers from range 0..519 or 1..520? — running.t
– running.t, Commented Dec 15, 2017 at 8:51
x = np.arange(1, 521), np.random.shuffle(x); x = x.reshape(65, 8) — cs95
– cs95, Commented Dec 15, 2017 at 8:55

running.t · Accepted Answer · 2017-12-15 09:05:44Z

3

In my opinion the easiest way would be to simply shuffle range of elements i.e.

x = numpy.arange(1, 521)
numpy.random.shuffle(x)

and then reshape it to matrix you want using numpy.reshape

x = numpy.reshape(x, (65,8))

edited Dec 15, 2017 at 9:05

answered Dec 15, 2017 at 8:55

running.t

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2 Comments

cs95 Over a year ago

You can do this with numpy's methods, they should be faster.

running.t Over a year ago

@cᴏʟᴅsᴘᴇᴇᴅ: Right. Edited:)

tsomi · Accepted Answer · 2017-12-15 09:39:08Z

0

Thank you a lot! However, I think the right answer is:

x = np.arange(1, 521).reshape((65, 8))
np.random.shuffle(x)

answered Dec 15, 2017 at 9:39

tsomi

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