Java.Lang.ClassNotFoundException: <Timeout exceeded getting exception details>

Question

i have very simple xamarin application , with 2 activities , when i want to start my second activity xamarin in visual studio 2017 show "Java.Lang.ClassNotFoundException: " ERROR

Can you please post the full error in question? You can use the Continue button when the UnhandledException dialog appears to the point of breaking out of debugging mode and view your Output window to see the full stack trace. — Jon Douglas
– Jon Douglas, Commented Dec 16, 2017 at 20:09
full Error : Java.Lang.ClassNotFoundException: <Timeout exceeded getting exception details> — user3248745
– user3248745, Commented Dec 17, 2017 at 6:01
Please post your code that how did you open your second activity and your second Activity code. — York Shen
– York Shen, Commented Dec 18, 2017 at 8:37

user9162497 · Accepted Answer · 2018-01-02 05:57:19Z

0

Maybe...

(ref.: https://developer.xamarin.com/guides/android/getting_started/hello,android_multiscreen/hello,android_multiscreen_quickstart/)

This work:

translationHistoryButton.Click += (sender, e) =>
{
    var intent = new Intent(this, typeof(TranslationHistoryActivity));
    intent.PutStringArrayListExtra("phone_numbers", phoneNumbers);
    StartActivity(intent);
};

This get Java.Lang.ClassNotFoundException:

translationHistoryButton.Click += (sender, e) =>
{
    var intent = new Intent(this, typeof(TranslationHistoryActivity));
    //intent.PutStringArrayListExtra("phone_numbers", phoneNumbers);
    //StartActivity(intent);
};

answered Jan 2, 2018 at 5:57

user9162497

1

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Khin Sandar · Accepted Answer · 2020-02-11 08:29:22Z

0

Install 'Android Support Repository' Tool->Android->Android SDK manager->Tools->Extras->Android Support Repository

After installed, Rebuild your project.

answered Feb 11, 2020 at 8:29

Khin Sandar

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