validate a password using regex followed by a pattern

Question

we need to check if the security password is documented correctly for an Internal Web CRM.

Is there a way to validate a given security password like a "$$$$Addy1234"?

This password string contains 4 Special Char, 4 Alphabets and 4 Number.And Alphabets part should contain one Upper and one Lower Case Character.

The regex I tried that work with all the case but in the Alphabets, I need to get at least one Upper and one Lower Case Character.

I tried following but can't get a solution:

$("#btn_submit").click(function () {

    if ($("#txt_pasword").filter(function () {
        return this.value.match(/^([-\/@#!*$%^&.'_+={}()]{4})([a-zA-Z]{4})([0-9]{4})$/);
    })) {
        $("#txt_pasword").parent().child("span").text("pass");
    } else {
        $("#txt_pasword").parent().child("span").text("fail");
    }

});

Please provide an idea how should I do this?

Thank you in advance.

Hi @Addy.Please read through this and see if this helps ->stackoverflow.com/questions/1559751/… — Sunil Hari
– Sunil Hari, Commented Dec 18, 2017 at 12:02
@Liam actually I want a regex which validates this string contains case as I provide in my Question there all the case I match except the Alphabets part which contains at least one lower and one upper case letter. — A.D.
– A.D., Commented Dec 18, 2017 at 12:06

Kalaiselvan · Accepted Answer · 2017-12-18 12:24:24Z

2

In the below code you can use your own logic for display error message but here I used alert

$(function(){
    $("#btn_submit").click(function () {
        var mat_str=/^([-\/@#!*$%^&.'_+={}()]{4})((?=.*[a-z])(?=.*[A-Z])(?=.*\d)[a-zA-Z\d]{4,})([0-9]{4})$/;
        var pass=$("#txt_pasword").val();
          if(pass!=null && pass!=undefined){
              if(mat_str.test(pass)){
              alert("pass");                
              }else{
              alert("fails");
              }
          }else{
              alert("Please Enter password");
          }
    });
})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>

<input type="password" id="txt_pasword">
<span></span>
</div>
<input type="button" id="btn_submit" value="submit"/>

edited Dec 18, 2017 at 12:24

answered Dec 18, 2017 at 12:07

Kalaiselvan

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3 Comments

A.D. Over a year ago

this also not work if the string does not contain an upper or lower char.

Kalaiselvan Over a year ago

@addy it will work based on your regexp /^([-\/@#!*$%^&.'_+={}()]{4})([a-zA-Z]{4})([0-9]{4})$/ i taken this from your question based on your try

A.D. Over a year ago

sorry buddy also have an issue with alphabets part this also provides a match if the string does not contain an upper or lower case char.

Ronnie Oosting · Accepted Answer · 2017-12-18 12:42:02Z

1

Would this help you?

Code:

$(document).ready(function() {
    var str = "$$$$Addy1234";
    var res = str.substring(0,3);
    var res2 = str.substring(4,7);
    var res3 = str.substring(8, 11);
    var check = 0;
    // check special chars
    if (res.match(/([!,%,&,@,#,$,^,*,?,_,~])/))
    {
        check += 1;
    }

    // check upper/lower cases
    if (res2.match(/([a-z].*[A-Z])|([A-Z].*[a-z])/))
    {
        check += 1;
    }

    // check numbers
    if (res3.match(/([0-9])/))
    {
        check += 1;
    }

    if( check < 3)
    {
        // return false
    }

    if (check === 3)
    {
        // return true
    }
});

You can make different checks:

// If password contains both lower and uppercase characters, increase strength value.
        if (password.match(/([a-z].*[A-Z])|([A-Z].*[a-z])/)) strength += 1
// If it has numbers and characters, increase strength value.
        if (password.match(/([a-zA-Z])/) && password.match(/([0-9])/)) strength += 1
// If it has one special character, increase strength value.
        if (password.match(/([!,%,&,@,#,$,^,*,?,_,~])/)) strength += 1
// If it has two special characters, increase strength value.
        if (password.match(/(.*[!,%,&,@,#,$,^,*,?,_,~].*[!,%,&,@,#,$,^,*,?,_,~])/)) strength += 1

You can check your own regex based on what given.

Using substring you can check specific length with a start and end.

Will this do it for you? Let me know! :)

edited Dec 18, 2017 at 12:42

answered Dec 18, 2017 at 12:00

Ronnie Oosting

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6 Comments

A.D. Over a year ago

Good try boy but there I have an issue with a password with a specific count of chars.This works individual like my tried regex but not accomplish my task

Ronnie Oosting Over a year ago

So if I understood it correctly: You need to check the first 4 chars, the next 4 and the last 4 (in your situation)?

Ronnie Oosting Over a year ago

Do you know about charAt and substring?

A.D. Over a year ago

Yes, But this not an answer and suggestion for my question.

A.D. Over a year ago

Let us continue this discussion in chat.

|

A.D. · Accepted Answer · 2017-12-19 08:05:57Z

1

Thanx to all people who provide me solution for this problem mainly @kalaiselvan-a and @ronnie-oosting.

But from the idea @kalaiselvan-a give than approximately correct with few of issue but this one helps me to get the solution accordingly.

Used Regex is :

/^([-\/@#!*$%^&.'_+={}()]{4})((?=.*[a-z])(?=.*[A-Z])[a-zA-Z]{4})([0-9]{4})$/

1st Capturing Group ([-\/@#!*$%^&.'_+={}()]{4}) Matches exactly 4 times character in the list @#!*$%^&.'_+={}() (case sensitive)

2nd Capturing Group ((?=.*[a-z])(?=.*[A-Z])[a-zA-Z]{4}) Matches exactly 4 times character in the list [a-z] and [A-Z] with one of each

3rd Capturing Group ([0-9]{4}) Matches exactly 4 times a character present in the list [0-9]{4}

answered Dec 19, 2017 at 8:05

A.D.

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