How do i dynamically assign a name to a php object?
for example how would i assign a object to a var that is the id of the db row that i am using to create objects.
for example
$<idnum>= new object();
where idnum is the id from my database.
-
Your question is confusing and hard to understand. Could you clarify it a bit?Henrik Paul– Henrik Paul2009-01-26 06:56:49 +00:00Commented Jan 26, 2009 at 6:56
Add a comment
|
4 Answers
You can use the a double dollar sign to create a variable with the name of the value of another one for example:
$idnum = "myVar";
$$idnum = new object(); // This is equivalent to $myVar = new object();
But make sure if you really need to do that, your code can get really messy if you don't have enough care or you abuse of using this "feature"...
I think you can better use arrays or hash tables rather than polluting the global namespace with dynamically created variables.
answered Jan 26, 2009 at 7:03
Christian C. Salvadó
831k185 gold badges929 silver badges845 bronze badges
Comments
this little snippet works for me
$num=500;
${"id$num"} = 1234;
echo $id500;
basically just use the curly brackets to surround your variable name and prepend a $;
Comments
You can do something like this:
${"test123"} = "hello";
echo $test123; //will echo "hello"
$foo = "mystring";
${$foo} = "a value";
echo $mystring; //will echo "a value";
