Creating n Object of array in java

Question

I am having issues understanding how to create an array of n objects in Java.

This is the constructor of class ServicePath as follows:

public ServicePath(String id) {
   this.id = id;
}

This is the elements of the array that I would like to create the objects.

String ServicePathArrays[] = {"SH11","SH13","SH17","SH110","SH111","SH112","SH115", ...}

I tried the following, but it creates it manually.

ServicePath[] servicePathArray = new ServicePath[ServicePathArrays.length];

For example, manually it creates the following

ServicePath[0] = new ServicePath("SH11");
ServicePath[1] = new ServicePath("SH13");
..
..

I would like to create it automatically using String ServicePathArrays in such way:

ServicePath[0].id = "SH11";
ServicePath[1].id = "SH12";
ServicePath[2].id = "SH13";
..
..

Are you looking for the most compact way of doing it?

kryger
– kryger

2017-12-20 11:18:40 +00:00
Commented Dec 20, 2017 at 11:18 — kryger
– kryger, Commented Dec 20, 2017 at 11:18

kryger · Accepted Answer · 2017-12-20 19:56:12Z

1

This could be done using the functional behavior of jdk8+ :

String servicePathArray[] = {"SH11", "SH13", "SH17",
                             "SH110", "SH111", "SH112", "SH115"};
List<ServicePath> collection = Stream.of(servicePathArray)
                                     .map(ServicePath::new)
                                     .collect(Collectors.toList());

System.out.println(collection);

edited Dec 20, 2017 at 19:56

kryger

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answered Dec 20, 2017 at 11:20

Mustapha Belmokhtar

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2 Comments

DodgyCodeException Over a year ago

It's more succinct to have Stream.of(servicePathArray) than Arrays.asList(servicePathArray).stream(). And even more succinct is Stream.of("SH11", "SH13", ..., "SH115").

Mustapha Belmokhtar Over a year ago

I agree :+1 for this hint

Nagendra Varma · Accepted Answer · 2017-12-20 11:19:59Z

1

String ServicePathArrays[] = {"SH11","SH13","SH17","SH110","SH111","SH112","SH115", ...};
ServicePath[] servicePathArray = new ServicePath[ServicePathArrays.length];
for(int i = 0; i < ServicePathArrays.length; i++) {
    servicePathArray [i] = new ServicePath(ServicePathArrays[i]);
}

answered Dec 20, 2017 at 11:19

Nagendra Varma

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