Sass Dynamic Variable in Loop

Question

How to get mixin argument from array variable in a loop with Sass? Example code is below:

$colors: red green blue;
    $red-foo: 100px;
    $red-bar: 110px;
    $red-baz: 120px;
    $green-foo: 100px;
    $green-bar: 110px;
    $green-baz: 120px;
    $blue-foo: 100px;
    $blue-bar: 110px;
    $blue-baz: 120px;
    
    @mixin item($color-foo, $color-bar, $color-baz){
        width: $color-foo,;
        height: $color-bar;
        ...
    }
    
    @each $color in $colors {
        .class-#{$color}{
            @include item($color#{-foo}, $color#{-bar}, $color#{-baz})
        }
    }

Desired output is below:

    .class-red{
        //variables
    }
    
    .class-green{
        //variables
    }
    
    .class-blue{
        //variables
    }

Also is there a way for shorthand of $color-foo, $color-bar, $color-baz like @include item($color-shorthand)? Maybe there could be a better solution for this.

Jaredcheeda · Accepted Answer · 2017-12-20 20:15:16Z

5

You want Sass Maps

$colors: (
    red: (
        foo: 100px,
        bar: 110px,
        baz: 110px
    ),
    green: (
        foo: 200px,
        bar: 210px,
        baz: 220px
    ),
    blue: (
        foo: 300px,
        bar: 310px,
        baz: 320px
    )
);

@mixin item ($color-foo, $color-bar, $color-baz) {
    width: $color-foo;
    height: $color-bar;
    padding: $color-baz;
}

@each $name, $value in $colors {
    .class-#{$name} {
        @include item(
            map-get($value, foo),
            map-get($value, bar),
            map-get($value, baz)
        );
    }
}

answered Dec 20, 2017 at 20:15

Jaredcheeda

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