Selecting selectbox options by array values

Question

I am getting some values via json type ajax request with Jquery. When I use alert(msg.options) it alerts ["1","3","8"]

If I use below script to select needed options, it works. It selects only options that have value 1 and 3 and 8 :

$('#input_6').val(["1","3","8"]);

But below script doesn't work even if it alerts the same:

$('#input_6').val(msg.options);

How can I fix this? Thank you...

You have to parse the JSON first. msg.options seems to be a string. If it would be an array, alert would show 1,3,8. @Falcon's answer is probably right (despite typo), no clue why he deleted it. But to be certain about this you would have to show the JSON and how you handle the response. — Felix Kling
– Felix Kling, Commented Jan 25, 2011 at 11:43
Oh and I just read that you are using dataType: json for the Ajax request. Then it seems you are building the JSON not correctly (or at least not suitable) for your situation. — Felix Kling
– Felix Kling, Commented Jan 25, 2011 at 11:50

Mike Tunnicliffe · Accepted Answer · 2011-01-25 11:46:01Z

3

Try:

$('#input_6').val($.parseJSON(msg.options));

answered Jan 25, 2011 at 11:46

Mike Tunnicliffe

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8 Comments

karim79 Over a year ago

This is the correct answer. The fact that '["1","3","8"]' was alerted instead of '1,3,8' means that msg.options is not an object but a string.

aiternal Over a year ago

Great. Thank you very much @fd . It works. I guessed the problem something about Json but couldn't find what it is. Thanks. :)

user447356 Over a year ago

+1 for the correct approach.. by the way you can't get notifications using @ as the minimum are 3 letters - are you aware of this?

Felix Kling Over a year ago

@Ahmet Kemal: Check how build the JSON. You can avoid the extra parsing if you build it correctly. This would really solve the problem and not just compensate it.

aiternal Over a year ago

@Shadow Wizard no I dont know what it is. Whatelse can I use to mention fd? @Felix King I think there is no problem about Json. It works properly now. Thanks.

|

Andrew Jackman · Accepted Answer · 2011-01-25 11:47:32Z

0

$(document).ready(function () {
    var msg = {};
    msg.options = '["1","3","8"]'
    $('#input_6').val( eval( msg.options ) );
});

http://jsfiddle.net/yjHUS/2/

answered Jan 25, 2011 at 11:47

Andrew Jackman

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1 Comment

aiternal Over a year ago

@Sydnam thank you for help. First answer works and also simple.

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