how to use php to loop through array to validate the value

Question

I have this array

array(6) {
  [0]=>
  string(7) "1234567"
  [1]=>
  string(5) "7548#"
  [2]=>
  string(9) "1254#abc#"
  [3]=>
  string(5) "32514"
  [4]=>
  string(6) "2548##"
  [5]=>
  string(5) "3258#"
}

I want to validate this data based on provided condition.

If ID(array[0] and array[3] or array[n]) is an integer check the *data* which is(array[1] and array[4] or array[n]) and if that data not contain more then one #, return false;

here is my sample code, but I'm only able to check the first and 2nd array,

if(preg_match('/^[1-7]{1,7}$/', current($arr))){
  next($arr);  
  if(substr_count(next($arr),"#") <=1)
     //false
  else
    echo "true";  
}

help needed, thanks.

Your question is not clear...

Gyandeep Sharma
– Gyandeep Sharma

2017-12-22 08:32:18 +00:00
Commented Dec 22, 2017 at 8:32 — Gyandeep Sharma
– Gyandeep Sharma, Commented Dec 22, 2017 at 8:32

Nigel Ren · Accepted Answer · 2017-12-22 08:46:04Z

2

You can use a for loop, which allows you to control the start point, the condition when to stop and the step your using, so...

$arr = ["1234567", "7548#", "1254#abc#", "32514", "2548##", "3258#"];
for ( $i = 0; $i < count($arr); $i+=3)  {
    echo $arr[$i].PHP_EOL;
    if ( preg_match('/^[1-7]{1,7}$/', $arr[$i]) ) {
        if(substr_count($arr[$i+1],"#") > 1)    {    // Check if it's +1 or +2 here
            echo "true".PHP_EOL;
        }
        else    {
            echo "false".PHP_EOL;
        }
    }
}

This loops from the start to the number of elements in your source, but just every 3rd item. The rest uses similar code to what you've already got, but using the array elements relative to the loop counter ($arr[$i+1] for example). You will have to check if this is the right element you want to check as it may be $arr[$i+2], but the concept is the same.

This outputs..

1234567
false
32514
true

One thing I would recommend is to try and write if statements so that you always get something from it being 'true'. In your code you use <=1 and then there is nothing to do - if you change that round to >1, then it means you can get rid of the 'empty' statement.

edited Dec 22, 2017 at 8:46

answered Dec 22, 2017 at 8:40

Nigel Ren

57.2k11 gold badges49 silver badges59 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Tony Over a year ago

thanks a a lot nigel, by the way, how can I do that also using javascript.??

Nigel Ren Over a year ago

Javascript would be virtually the same, for loops like this are common in most languages.

Hakan SONMEZ · Accepted Answer · 2017-12-22 08:37:24Z

2

you need to create a loop then you can write your rules for specific n.

$n = 3; //Your modulo
for($x = 0, $l = count($array); $x < $l; $x++ ) { //$array is your array
   if($x % $n == 0) {
       $result = preg_match('/^[1-7]{1,7}$/',$array[$x]);
   } else if ($x % $n == 1) {
       $result = substr_count($array[$x], '#') > 1;
   } else {
       $result = true; //no specific rule
   }

   if(!$result) { //if validation fails
      echo "Validation failed";
      break;
   }
}

answered Dec 22, 2017 at 8:37

Hakan SONMEZ

2,2342 gold badges23 silver badges35 bronze badges

Collectives™ on Stack Overflow

how to use php to loop through array to validate the value

2 Answers 2

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related