Nice day for all!
I need to fill the "global" array with other arrays. As an example, I wrote this function:
<?php
function f($ar=array(), $gl=array()){
$gl[0]=array($ar[1]);
}
$globals=array();
$array_example=array('foo', 'bar');
f($array_example, $globals);
print_r($globals); //$globals is empty!
?>
Help me please. I can not understand why the var $globals is empty.
Thanks!
I think you should pass the array by reference using &:
function f($ar = array(), &$gl = array())
{
$gl[0] = array($ar[1]);
}
$globals = array();
$array_example = array('foo', 'bar');
f($array_example, $globals);
print_r($globals);
Will give you:
Array
(
[0] => Array
(
[0] => bar
)
)
man first you should modify the function to return the value and assign the returned value for the value to be printed .
you are print the $global and it is an empty array .
so your code should be like this .
<?php
function f($ar = array(), $gl = array()){
$gl[0] = array($ar[1]);
return $gl;
}
$globals=array();
$array_example=array('foo', 'bar');
$globals = f($array_example, $globals);
print_r($globals);
// prints out Array ( [0] => Array ( [0] => bar ) )
?>
Function always works on locally variables, And you want to use their locally variable scope to out of function. Check with below code, I hope it will help you
function f($ar=array(), $gl=array()){
return array($ar[1]);
}
$globals=array();
$array_example=array('foo', 'bar');
$tmpArray = f($array_example, $globals);
$globals[0]=$tmpArray;
print_r($globals);