Convert string to object in typescript?

Question

I am trying to validate a glob expression using Is-Valid-Glob which accepts string and array. The value which needs to be validated is received from a text field. The problem is that if we pass an invalid glob expression it produces the wrong result as every input is received as a string. For example:- If user inputs [] (invalid glob) its gets assigned to model variable as string '[]' and validation is done on '[]' instead of [] value. Is there a way by which we convert the value from string variable to object variable (only the value should not get type) and do validation?

PS: I am using Angular 2.

please consider reading the asking help to ask a valid and quality post — Aravind
– Aravind, Commented Dec 26, 2017 at 6:13

Vikramjit Roy · Accepted Answer · 2017-12-26 08:51:44Z

6

You can use JSON.parse to convert from string to objects:

     var x = require('is-valid-glob');
     var y = '[]';//'foo/*.js' any user provided string
     // this will check if the user has provided an array object if so it 
     //will do a json.parse to remove the '' and then verify the string for a glob.
     x(y[1] !== '['?y:JSON.parse(y));

answered Dec 26, 2017 at 8:51

Vikramjit Roy

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1 Comment

Akshay Over a year ago

Hi @Vikramjit, I am using the similar hack serves the purpose. Looking for a more satisfiable solution. Also, need to add cases for {} (invalid glob), it will pass in this scenario

Deepak Jha · Accepted Answer · 2017-12-26 06:48:44Z

3

Try with eval it is used to convert string into equivalent object for an example,

var a="[]";
console.log(a);// this will print "[]" as a string.
console.log(eval(a));// this will print an array object. With 0 length array object.

answered Dec 26, 2017 at 6:48

Deepak Jha

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Akshay Over a year ago

thanks, @deepak, eval will not be helpful in case of strings. eg "foo/*.js" (valid glob).

Sanjeeta · Accepted Answer · 2019-11-27 01:54:05Z

-2

We can use Object.assign({},object) to convert string into object.

answered Nov 27, 2019 at 1:54

Sanjeeta

1

1 Comment

Noam Gal Over a year ago

Doesn't work. In case of a string, it splits the string to an array where each element is a single character from that string.

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