I'm trying to upload a video file to my server using a post request.
var file = new File(videoPath);
var uri = Uri.parse(tokenizedUri);
HttpClientRequest request = await new HttpClient().postUrl(uri);
await request.addStream(file.openRead());
var response = await request.close();
response.transform(utf8.decoder).forEach((string) {
print(string); // handle data
});
But the server doesn't get it. Why?
The correct way is to use a MultipartRequest:
var uri = Uri.parse(url);
var request = new MultipartRequest("POST", uri);
var multipartFile = await MultipartFile.fromPath("package", videoPath);
request.files.add(multipartFile);
StreamedResponse response = await request.send();
response.stream.transform(utf8.decoder).listen((value) {
print(value);
});
request.fields['title'] = title.text; request.fields['sub_title'] = subTitle.text; var profile_photo = await MultipartFile.fromPath("profile_photo", photo.path); request.files.add(profile_photo); request.files .add(await http.MultipartFile.fromPath('profile_video', video.path)); var response = await request.send(); var responseString = await response.stream.bytesToString(); print(responseString); {sub_title":"dd","profile_photo":{},"profile_video":{}}You can use the Dio package. It supports large files and works fine with me.
sendFile(String kMainUrl, XFile file) async {
String filePath = file.path;
String fileName = 'any name';
try {
FormData formData = FormData.fromMap({
"file":
await MultipartFile.fromFile(filePath, filename:fileName),
});
Response response =
await Dio().post(kMainUrl, data: formData);
print("File upload response: $response");
print(response.data['message']);
} catch (e) {
print("Exception Caught: $e");
}
}
