I want to do something like this:
const foo = ['aba', 'bab'];
const bar = [1, 2];
and then create this array:
result = [
{
text: foo[0]
number: bar[0]
},
{
text: foo[1]
number: bar[1]
}
]
Foo and bar will have equal lengths.
5 Answers
If your arrays have same length, you can use Array#map to iterate over each item, get the item and the index and then create the new array of objects setting the text to item and the number to bar[index].
const foo = ['aba', 'bab'];
const bar = [1, 2];
const mapped = foo.map((item, index) => ({text: item, number: bar[index]}));
console.log(mapped);Comments
I would simply map one of the array and use the second parameters of the mapping function, the index, to get the value for the other one:
var result = foo.map((value, index) => ({
text: value, number: bar[index],
}));
Comments
Simple solutin
let result = [] ;
const foo = ['aba','bab']
const bar = [1,2]
for(let i = 0 ; i<foo.length;i++){
result[i]={}
result[i].text = foo[i] ;
result[i].number = bar[i];
}
console.log(result) ;
Comments
Assuming the are always the same length, you can do:
var foo = ['aba','bab']
var bar = [1,2]
function makeObjects(f, b) {
return foo.map((o, i) => ({text: f[i], number: bar[i]}))
}
console.log(makeObjects(foo, bar))
// [{text: 'aba', number: 1}, {text: 'bab', number: 2}]
Comments
var foo = ['aba','bab'];
var bar = [1,2];
var result = [];
function a(){
for(var i=0;i<foo.length;i++){
result[i] = { text: foo[i], number:bar[i]};
}
console.log(result);
}
is this what you are looking for?
fooandbaralways be the same length?