Regex string extraction

Question

I am stumped working on a regular expression. So here is the sample text I am working with to run my regex on.

21;#ABC - A8 (ZYWX) DEF - S123 CODE ASD4 - PL_MN - 567aB - 987aL 6.8R WHHHA StackOverflow.file;42;#ABC_9876f_KIIIt_QW_blew34.files;43;#ABC-LKP RT00-44-33 [email protected];45;#Javax_P3_2345_123lE_451rP_Regex_Expression_Help.rewa;26;#GHJ - AQS 231-4_330-9 TIIIx Python JavaScript.text;

Here is the end result I am looking for after running the regex:

ABC - A8 (ZYWX) DEF - S123 CODE ASD4 - PL_MN - 567aB - 987aL 6.8R WHHHA StackOverflow  
ABC_9876f_KIIIt_QW_blew34  
ABC-LKP RT00-44-33 876aY@2200foo  
Javax_P3_2345_123lE_451rP_Regex_Expression_Help  
GHJ - AQS 231-4_330-9 TIIIx Python JavaScript

A total of 5 matches.

The regular expression I have thus far is:

[A-Z][()\w\s@-]*

This regex isn't working though because the first line in my results ends up getting split in two pieces at the period. I am unable to come up with a solution as to how to fix this. I am fairly new to regex so any help would be appreciated. Thank you.

So the . after StackOverflow is a delimiter, but the . in 6.8R is not? — Barmar
– Barmar, Commented Jan 3, 2018 at 20:10
It looks like all your matches end with .<word>;, is that correct? Use a positive lookahead to match that. — Barmar
– Barmar, Commented Jan 3, 2018 at 20:12

Barmar · Accepted Answer · 2018-01-03 20:16:16Z

1

It looks like each match ends with ., followed by a word, followed by ;. Use a positive lookahead to match a string followed by that.

[A-Z][()\w\s@\-.]*(?=\.\w+;)

DEMO

edited Jan 3, 2018 at 20:16

answered Jan 3, 2018 at 20:15

Barmar

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2 Comments

ctwheels Over a year ago

[A-Z][()\w\s@\-.]*(?=\.\w+;) <- errors out without escaped -

Nizzy Over a year ago

Yes. That works. Thank you for your help and such quick response. Looks like I have some learning to do on lookaheads.

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