Cut string until specified character. Bash

Question

I'm trying to cut a string until it's first specified characters. in this case, it's first Latin letter.

I tired this. It kind of works but sometimes shifts 1 or more characters.

f=$(echo $f | tail -c $((${#f}+-$(expr index "$f" [azertyuiopqsdfghjklmwxcvbnAZERTYUIOPQSDFGHJKLMWXCVBN])+2)))

take this string as example: ã%82¹ã%83%91ã%83¼ã%82¯ã%83«__original_ver.__-Your_name.mp3

I want to get: original_ver.__-Your_name.mp3 I tend to get this instead: ver.__-Your_name.mp3

Is there a better method? if so, some explanation is always welcome.

PesaThe · Accepted Answer · 2018-01-04 20:30:22Z

1

f=$(shopt -s extglob; LC_ALL=C; echo "${f##+([^[:alpha:]])}")

f=$(shopt -s extglob; LC_ALL=C; echo "${f/#+([^[:alpha:]])}")

f=$(LC_ALL=C sed -r 's/^[^[:alpha:]]+//' <<< "$f")

Setting LC_ALL to C is mandatory, otherwise [[:alpha:]] might match wrong characters.

answered Jan 4, 2018 at 20:30

PesaThe

7,5691 gold badge23 silver badges47 bronze badges

Sign up to request clarification or add additional context in comments.

1 Answer 1