php regular expression find and replace

Question

$string = '20110306';
$pattern = '(\d{6})(\d{2})';
$replacement = '$101';
echo preg_replace($pattern, $replacement, $string);

I want it to echo 20110301

I used http://gskinner.com/RegExr/ to come up with the search and replacement pattern, maybe I am missing something when it comes to replacing the found pattern.

It gives me the following warning:

Message: preg_replace() [function.preg-replace]: Unknown modifier '('

codaddict · Accepted Answer · 2011-01-27 17:21:51Z

5

Two changes:

You need to place the regex between a pair delimiters, say / as::
```
$pattern = '/(\d{6})(\d{2})/';
```
$101 refers to group number 101. You meant to append 01 to group number 1 so change
```
$replacement = '$101';
```
to
```
$replacement = '${1}01';
```

See it

edited Jan 27, 2011 at 17:21

answered Jan 27, 2011 at 16:46

codaddict

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Comments

powtac · Accepted Answer · 2011-01-27 16:46:33Z

0

replace the () by ~~ in $pattern.

answered Jan 27, 2011 at 16:46

powtac

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1 Comment

Spudley Over a year ago

or indeed, any other valid regex delimiter character.

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