I have a String[] that has at least 2 elements.
I want to create a new String[] that has elements 1 through the rest of them. So.. basically, just skipping the first one.
Can this be done in one line? easily?
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3 Answers
Use copyOfRange, available since Java 1.6:
Arrays.copyOfRange(array, 1, array.length);
Alternatives include:
ArrayUtils.subarray(array, 1, array.length)from Apache commons-langSystem.arraycopy(...)- rather unfriendly with the long param list.
4 Comments
Mark Peters
The end index is exclusive
NullVoxPopuli
Wait, so does that mean I need a +1 to the .length?
ILMTitan
No, because arrays are 0 based. Half open ranges and 0 based indexing work together nicely like that.
matthaeus
Sorry java-folks, but, coming from python code this looks just absurd
String[] subset = Arrays.copyOfRange(originalArray, 1, originalArray.length);
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Comments
Stream API could be used too:
String[] array = {"A", "B"};
Arrays.stream(array).skip(1).toArray(String[]::new);
However, the answer from Bozho should be preferred.
1 Comment
Grzegorz Piwowarek
@AndreaBergonzo unfortunately, they provided methods for
String[], int[], long[], double[] but not for byte[] :)