Filter JSON arrays with nested array filters combined

Question

I'm writing a JS code that has to filter JSON data based on a condition. I've posted a question yesterday but without trying anything at How to filter data from a json response, it was down voted and since I didn't try anything I am good with it. I've tried using the filter, but unfortunately I've got an array with in array and here I'm stuck. Here is my code.

var arr2 = [
  [{
    "max": "0.685",
    "target_state": "6",
    "ingredients": "a",
    "rule_no": "7",
    "id": "18"
  }, {
    "max": "14",
    "target_state": "6",
    "ingredients": "b",
    "rule_no": "7",
    "id": "17"
  }],
  [{
    "max": "14",
    "target_state": "7",
    "ingredients": "b",
    "rule_no": "8",
    "id": "19"
  }, {
    "max": "1.36",
    "target_state": "7",
    "ingredients": "a",
    "rule_no": "8",
    "id": "20"
  }]
];

var result = arr2.reduce(function(a, b) {
    return a.concat(b);
  })
  .filter(function(obj) {
    return (obj.max == 0.685 && obj.ingredients === "a")
  });

alert(JSON.stringify(result[0].target_state));

when I run this code, I get the result as "6".

But here my condition is something like this ((obj.max == 0.685 && obj.ingredients === "a") && (obj.max == 14 && obj.ingredients === "b")), but this is not returning anything.

Here the expected output is "6".

Here is a working fiddle https://jsfiddle.net/vjt45xv4/14/

Please let me know where am I going wrong and how can I fix this.

Thanks

Can you also share expected output based on max and ingredients value? — gurvinder372
– gurvinder372, Commented Jan 17, 2018 at 6:56
It should be (...) || (...). If obj.max is 0.685, it cannot be 14. Always try to write an English version of condition. It will always help in solving them. ((obj.max == 0.685 && obj.ingredients === "a") && (obj.max == 14 && obj.ingredients === "b")) is interpreted as max value should be 0.685 and ingredients should be a and max value should be 14 and ingredients should be b — Rajesh Dixit
– Rajesh Dixit, Commented Jan 17, 2018 at 6:58
Are you trying to select the first, second, and third elements, or just the first and second? Also, I would suggest not using == in order to compare a number to a string. If you want to compare a string value to a number, parse the string: Number(obj.max) === 0.685 — JLRishe
– JLRishe, Commented Jan 17, 2018 at 7:07
@JLRishe, Here I've an array like this [[{}, {}],[{}, {}]] and here I want to check the internal arrays matching the condition(both the internal arrays should satisfy it) and return the result. — user3872094
– user3872094, Commented Jan 17, 2018 at 7:09

Nabin Paudyal · Accepted Answer · 2018-01-17 09:16:00Z

1

I think I understand what you are trying to achieve here.

How about the following one? It worked for me.

var result = arr2
  .filter(function(objs) {
    return ((objs.find((obj) => obj.ingredients === "a" ).max == 0.685) 
&& (objs.find((obj) => obj.ingredients === "b" ).max == 14));
  })
  .reduce(function(a, b) {
    return a.concat(b);
  });

edited Jan 17, 2018 at 9:16

answered Jan 17, 2018 at 7:56

Nabin Paudyal

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6 Comments

user3872094 Over a year ago

Thanks for this friend. But I'm matching for both, not either

Nabin Paudyal Over a year ago

@user3872094 You want objects matching both the conditions within sub array?

user3872094 Over a year ago

Yes Nabin, you are perfect... That's my requirement

Nabin Paudyal Over a year ago

@user3872094 I now understand what you are trying to achieve. I have provided the solution. Please check.

user3872094 Over a year ago

You are awesome Bro ... This was what I was expecting :)

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