Typescript Array sorting

Question

How do I sort an array of objects alphabetically in Typescript. I have array in this format now - I am looking to sort it alphabetically by the channel field.

Here is what I tried which I got from the web.It didn't show any errors and also it didn't produce the expected result as well.

 this.currentPickSelection = this.currentPickSelection.sort((a, b) => {
      if (a.channel > b.channel) {
        return 1;
      }
      if (a.channel < b.channel) {
        return -1;
      }
      return 0;

Why each array has an array again inside? You've to change the JSON object. — Saiyaff Farouk
– Saiyaff Farouk, Commented Jan 20, 2018 at 7:06
Possible duplicate of Sort array by firstname (alphabetically) in Javascript — Tsvetan Ganev
– Tsvetan Ganev, Commented Jan 20, 2018 at 7:07
@Saiyaff, I am trying to do that, But I am not sure how it happens. — Sumchans
– Sumchans, Commented Jan 20, 2018 at 7:14
@Tsvetan Ganev Thats the link I got that code snippet from. I was not able to solve with that posting, thats why I created another one. — Sumchans
– Sumchans, Commented Jan 20, 2018 at 7:15

Hassan Imam · Accepted Answer · 2018-01-20 07:12:18Z

6

You have a multidimensional array. Your array#sort method should be

this.currentPickSelection.sort((a, b) => a[0].channel.localeCompare(b[0].channel))

answered Jan 20, 2018 at 7:12

Hassan Imam

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1 Comment

Sumchans Over a year ago

That Worked. Thanks @Saiyaff Farouk

Saiyaff Farouk · Accepted Answer · 2018-01-20 07:25:40Z

You basically have to sort an array of objects.

Change your JSON object as an array of objects.

[
    {
        "pickCode":"",
        "cbsCode": "",
        "channel": "",
        "logo": "",
        "tag": ""
    },
    {
        "pickCode":"",
        "cbsCode": "",
        "channel": "",
        "logo": "",
        "tag": ""
    },
    {
        "pickCode":"",
        "cbsCode": "",
        "channel": "",
        "logo": "",
        "tag": ""
    }
]

Write a reusable function like this. (Same logic you've used. I've added the toLowerCase() part)

private compare(a, b) {
 if (a.channel.toLowerCase() < b.channel.toLowerCase()) {
  return -1;
 }
 if (a.channel.toLowerCase() > b.channel.toLowerCase()) {
  return 1;
 }
 return 0;
}

And then, let's assume that arrayOfObjects variable name is channelDetails,

simply this.channelDetails.sort(this.compare); would do this.

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