How can I call SubGraphButton_Click(object sender, RoutedEventArgs args) from another method?
private void SubGraphButton_Click(object sender, RoutedEventArgs args)
{
}
private void ChildNode_Click(object sender, RoutedEventArgs args)
{
// call SubGraphButton-Click().
}
You can easily do it by the following piece of code (assuming that name of your button is btnButton):
btnButton.PerformClick();
You can call the button_click event by simply passing the arguments to it:
private void SubGraphButton_Click(object sender, RoutedEventArgs args)
{
}
private void ChildNode_Click(object sender, RoutedEventArgs args)
{
SubGraphButton_Click(sender, args);
}
SubGraphButton_Click() is async? And the method that needs to simulate the click isn't? This isn't the correct answer. The correct answer would be to call SubGraphButton.PerformClick() inside ChildNode_Click()
object sender = this; and RoutedEventArgs args. Then call it like normal: SubGraphButton_Click(sender, args);you can call the button_click event by passing..
private void SubGraphButton_Click(object sender, RoutedEventArgs args)
{
}
private void ChildNode_Click(object sender, RoutedEventArgs args)
{
SubGraphButton_Click(sender, args);
}
Also without passing..
private void SubGraphButton_Click(object sender, EventArgs args)
{
}
private void Some_Method() //this method is called
{
SubGraphButton_Click(new object(), new EventArgs());
}
You can perform different approaches to work around this. The best approach is, if your both buttons are suppose to do the same job, you can define a third function to do the job. for example :
private void SubGraphButton_Click(object sender, RoutedEventArgs args)
{
myJob()
}
private void ChildNode_Click(object sender, RoutedEventArgs args)
{
myJob()
}
private void myJob()
{
// Your code here
}
but if you are still persisting on doing it in your way, the best action is :
private void SubGraphButton_Click(object sender, RoutedEventArgs args)
{
}
private void ChildNode_Click(object sender, RoutedEventArgs args)
{
SubGraphButton_Click.PerformClick();
}
In WPF, you can easily do it in this way:
this.button.RaiseEvent(new RoutedEventArgs(Button.ClickEvent));
Usually the better way is to trigger an event (click) instead of calling the method directly.
private void PictureBox1_Click(object sender, EventArgs e)
{
MessageBox.Show("Click Succes");
}
private void TextBox1_KeyPress(object sender, KeyPressEventArgs e)
{
if (e.KeyChar == 13)
{
PictureBox1_Click(sender, e); //or try this one "this.PictureBox1_Click(sender, AcceptButton);"
}
}
You can simply call it:
SubGraphButton_Click(sender, args);
Now, if your SubGraphButton_Click does something with the args, you might be in trouble, but usually you don't do anything with them.
For me this worked in WPF
private void Window_KeyDown(object sender, KeyEventArgs e)
{
if (e.Key == Key.Enter)
{
RoutedEventArgs routedEventArgs = new RoutedEventArgs(ButtonBase.ClickEvent, Button_OK);
Button_OK.RaiseEvent(routedEventArgs);
}
}
Use InvokeOnClick event. it works even if the button is invisible/disabled
A simple way to call it from anywhere is just use "null" and "RoutedEventArgs.Empty", like this:
SubGraphButton_Click(null, RoutedEventArgs.Empty);
For WPF:
YourButtonName.RaiseEvent(new RoutedEventArgs(System.Windows.Controls.Primitives.ButtonBase.ClickEvent));
Add it to the instance of the Click delegate:
ChildNode.Click += SubGraphButton_Click
which is inkeeping with the pattern .NET events follow (Observer).
For people wondering, this also works for button click. For example:
private void btn_Click(object sender, EventArgs e)
{
MessageBox.Show("Test")
}
private void txb_KeyPress(object sender, KeyPressEventArgs e)
{
if (e.KeyChar == (char)13)
{
btn_Click(sender, e);
}
When pressing Enter in the textfield(txb) in this case it will click the button which will active the MessageBox.
we have 2 form in this project. in main form change
private void button1_Click(object sender, EventArgs e)
{
// work
}
to
public void button1_Click(object sender, EventArgs e)
{
// work
}
and in other form, when we need above function
private void button2_Click(object sender, EventArgs e)
{
main_page() obj = new main_page();
obj.button2_Click(sender, e);
}
