PHP: How can be protected variable accessed from child Class if he have different value?

Question

How can a protected variable be accessed from a child Class if it has a different value?

Example to wrong access: parent::$_my gives error

class Father{
  protected $_my=array('a','b');
}

class Child{
   protected $_my=array('c','d');
  function __construct(){
   parent::__construct();
   $this->_my=array_merge(parent::$_my,$this->_my);
  }
}

Thanks, Yosef

If you want the class to inherit from another, you must use the extends keyword - like Class Child extends Father — Michael Robinson
– Michael Robinson, Commented Jan 30, 2011 at 22:08
Protected variables can be accessed by children, that's how it works? $_my in Child will overwrite the values set in Father — Jake N
– Jake N, Commented Jan 30, 2011 at 22:10

Chris Heald · Accepted Answer · 2011-01-30 22:07:02Z

3

$this->_my will be inherited from the parent when you instantiate a subclass, so you simply need to use:

$this->_my = array_merge($this->_my, array('c','d'));

answered Jan 30, 2011 at 22:07

Chris Heald

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2 Comments

Ben Over a year ago

Thanks,It what i write in my application know , but how can i call with parent?

KingCrunch Over a year ago

As Chris mentioned, $_my is inherited from the parent, to the child. Its all the same and there is no "parent property". You access it like any other property via $this->_my.

iBiryukov · Accepted Answer · 2011-01-30 22:26:17Z

1

There is something wrong with you design. You have already declared a variable that can be accessed by child inside parent.

Try adding values to already existing variable, rather than redefining it.

answered Jan 30, 2011 at 22:26

iBiryukov

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