Passing parameters to powershell script from batch file

Question

I am calling a powershell script from a batch file, both in different locations.

I would like to pass the folder location for the powershell script file as well as the parameter, a user entered string in the batch file, from that batch file.

powershell script:

$url = "https://www.ons.gov.uk/generator?format=csv&uri=/economy/inflationandpriceindices/timeseries/chaw/mm23"
$output="sample.csv"
$start_time = Get-Date
$arg1=$args[0]
Invoke-WebRequest -Uri $url -OutFile $arg1\$output
Write-Output "Time taken: $((Get-Date).Subtract($start_time).Seconds) second(s)"

My Batch file :

powershell.exe -ExecutionPolicy Bypass -file C:\temp\download-rpi.ps1 "\\drives\savehere"

Why do you need a batch file at all? Just run your script from the PowerShell prompt. — Bill_Stewart
– Bill_Stewart, Commented Jan 26, 2018 at 14:34
@Bill_Stewart Because he can only call batch from the 3rd party software. — user7818749
– user7818749, Commented Jan 27, 2018 at 17:07
@Bill_Stewart He did not, no, he only mentioned in comments below in answers. — user7818749
– user7818749, Commented Jan 29, 2018 at 12:43

Armen Michaeli · Accepted Answer · 2021-05-31 13:41:05Z

3

You could have done all of this in a single language instead of using both Powershell and batch, but regardless, here is what you want

@echo off
if "%1"=="" (
    set /p "pspath=Enter the path to Powershell: "
    ) else set "pspath=%1"
if "%2"=="" (
    set /p "sharepath=Enter the share parameter: "
    ) else set "sharepath=%2"
    powershell.exe -ExecutionPolicy Bypass -file "%pspath% "%sharepath%"

How it works:

you can either double click the file which will then prompt for the powershell path and sharepath

OR

run from cmdline and enter the variables after the batch command, which will use %1 %2 to set the variables. Examples:

Double Clicking batch:

Enter the path to Powershell: C:\Some Path\
Enter The share parameter: \\some\share

Result

powershell.exe -ExecutionPolicy Bypass -file "C:\Some Path\" "\\some\share"

Running from cmd.exe prompt

C:\> BatchFileName.cmd "C:\Some Path\" "\\some\share"

Result

powershell.exe -ExecutionPolicy Bypass -file "C:\Some Path\" "\\some\share"

edited May 31, 2021 at 13:41

Armen Michaeli

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answered Jan 26, 2018 at 14:12

user7818749

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2 Comments

KKK Over a year ago

Thanks. It helped me to fix my problem

user7818749 Over a year ago

@Khushi glad I could help.

G42 · Accepted Answer · 2018-01-26 12:59:11Z

1

In PowerShell, this is done using parameters:

param(
    [string]$Path
)

$url        = "https://www.ons.gov.uk/generator?format=csv&uri=/economy/inflationandpriceindices/timeseries/chaw/mm23"
$output     = "sample.csv"
$start_time = Get-Date

Invoke-WebRequest -Uri $url -OutFile $Path\$output

Write-Output "Time taken: $((Get-Date).Subtract($start_time).Seconds) second(s)"

An alternative is to use the automatic variable $MYINVOCATION to get similar behaviour to an $args array but I would not recommend that as you have no way of knowing what unbound parameters will be provided.

$url        = "https://www.ons.gov.uk/generator?format=csv&uri=/economy/inflationandpriceindices/timeseries/chaw/mm23"
$output     = "sample.csv"
$start_time = Get-Date
$Path       = $MYINVOCATION.UnboundArguments

Invoke-WebRequest -Uri $url -OutFile $Path\$output

Write-Output "Time taken: $((Get-Date).Subtract($start_time).Seconds) second(s)"

answered Jan 26, 2018 at 12:59

G42

10.1k2 gold badges22 silver badges36 bronze badges

3 Comments

KKK Over a year ago

@gmsoylman : Thanks. now coming to batch file - instead of passing hardcoded path(as i passed in batch file for $path) how to pass them as parameters which can be provided at third party ? Also my batch file is in different folder so i would like to give the path of poweshell script as parameter

G42 Over a year ago

@Khushi Is there a reason you're using a batch file instead of pure PowerShell?

KKK Over a year ago

Yes. I am calling this batch file in a third part application which does not support calling powerscript file directly.

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