Retrieving part of URL in python [duplicate]

Question

I'm on Python 3.6. How I can extract part of URL so I can use it as variable. For example, the URL is http://example.com/comp/project.sec and I would like to get the project part without .sec as variable.

How can I achieve that?

umaru · Accepted Answer · 2018-01-29 11:33:55Z

2

url = "http://example.com/comp/project.sec"
project = url.split("/")[-1].split(".")[0]

edited Jan 29, 2018 at 11:33

answered Jan 29, 2018 at 11:27

umaru

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3 Comments

umaru Over a year ago

Sorry url = "example.com/comp/project.sec"

ViG Over a year ago

You can edit your answer to change that :)

umaru Over a year ago

@ViG thanks, bro =^_^=

jpp · Accepted Answer · 2018-01-29 11:38:55Z

2

Here's an alternative, which removes split requirement.

from os.path import splitext, basename

splitext(basename('http://example.com/comp/project.sec'))[0]

edited Jan 29, 2018 at 11:38

answered Jan 29, 2018 at 11:34

jpp

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2 Comments

Klaus D. Over a year ago

os.path.basename on a URL?

umaru Over a year ago

This is much better than my answer

user8098055 · Accepted Answer · 2018-01-29 11:36:11Z

0

import urllib
urllib.parse.urlparse("http://example.com/comp/project.sec").path.split("/")[-1].split(".")[-1]

answered Jan 29, 2018 at 11:36

user8098055

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