ParseException while parsing date from String to date Object

Question

I'm getting a ParseException while parsing a date from String to Date object. The date string also contains a timezone. I'm using this code:

final SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z");
System.out.print(sdf.parse("2018-01-16T00:07:00.000+05:30"));

Below is the error I'm getting:

Exception in thread "main" java.text.ParseException: Unparseable date: "2018-01-16T00:07:00.000+05:30"
    at java.text.DateFormat.parse(DateFormat.java:366)

what about the TO that exists between the date string??? you need to cater it too. — Farhan Qasim
– Farhan Qasim, Commented Jan 30, 2018 at 9:36
Well ... Does the parsed string follow the same format as the format specifier? — Seelenvirtuose
– Seelenvirtuose, Commented Jan 30, 2018 at 9:38
This exception happened because you are not matching the date you want to parse. — Antoine Dubuis
– Antoine Dubuis, Commented Jan 30, 2018 at 9:40
Try the answers provided in this link: stackoverflow.com/questions/17692863/… — srp321
– srp321, Commented Jan 30, 2018 at 10:06
@srp321, the answers found in the question you link to use SimpleDateFormat too, I recommend you avoid that and use java.time instead. See the modern and easy solution in the answer by Laurent B. — Anonymous
– Anonymous, Commented Jan 30, 2018 at 11:58

wss · Accepted Answer · 2018-01-31 10:55:00Z

4

The format you use in SimpleDateFormat must match the input String.

Your input is 2018-01-16T00:07:00.000+05:30, which is ISO8601 compliant:

year-month-day (2018-01-16)
followed by the letter T
followed by hour:minutes:seconds.milliseconds (00:07:00.000)
followed by the UTC offset (+05:30)

Note: the offset +05:30 is not a timezone. Read this to know the difference.

Anyway, the pattern you're using ("yyyy-MM-dd HH:mm:ss z") doesn't match the input string:

it's missing the T between date and time
it's missing the milliseconds
there's a space before the offset
the correct letter to parse offsets is X (although I think that z might work, depending on the JVM version you're using; in my tests, it didn't)

So your code should be:

// use "XXX" to parse the whole offset (only one "X" will parse just `+05`, missing the `:30` part)
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSXXX");
Date d = sdf.parse("2018-01-16T00:07:00.000+05:30");

But it's much better to use the new Java 8 classes, if they're available to you:

// parse ISO8601 compliant string directly
OffsetDateTime odt = OffsetDateTime.parse("2018-01-16T00:07:00.000+05:30");

If you still need to use a java.util.Date object, it's easy to convert:

// convert to java.util.Date
Date date = Date.from(odt.toInstant());

answered Jan 31, 2018 at 10:55

wss

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1 Comment

Anonymous Over a year ago

Very well explained answer, thanks. Agree to use the Java 8 classes. New? Only four years old. :-) Available in Java 6 and 7 too through the ThreeTen Backport.

Akshay · Accepted Answer · 2018-01-30 10:00:59Z

1

Change the following:

final SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss Z");
          System.out.print(sdf.parse("2018-01-16 0:07:00 +0530"));

You are trying to parse z which stands for General time zone eg GMT IST etc but you need Z zone-offset like +0530 for India.Also remove the OT between the string. Your date format should match with the pattern. Refer https://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html

edited Jan 30, 2018 at 10:00

answered Jan 30, 2018 at 9:41

Akshay

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2 Comments

Laurent B Over a year ago

RFC 822 is the ARPA Internet Text Messages specification. The format OP is using is correct according to the ISO 8601

Akshay Over a year ago

@LaurentB see my edit..z time-zone name zone-name Pacific Standard Time; PST while Z zone-offset offset-Z +0000; -0800; -08:00; is what I am trying to say..which is just another approach to solve the problem

Laurent B · Accepted Answer · 2018-01-30 11:18:19Z

1

Your are using an ISO 8601 date.

Using SimpleDateFormat :

final SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'.'SSSX");
System.out.print(sdf.parse("2018-01-16T00:07:00.000+05:30"));

Alertnatively, you can use the build in ISO 8601 parsing provided :

Using joda time Instant:

Instant.parse("2018-01-16T00:07:00.000+05:30")

JAVA 8 : (prefered see comment below)

https://docs.oracle.com/javase/8/docs/api/java/time/OffsetDateTime.html#parse-java.lang.CharSequence-

    System.out.println(java.time.OffsetDateTime.parse(s));

edited Jan 30, 2018 at 11:18

answered Jan 30, 2018 at 9:41

Laurent B

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3 Comments

Rahul Over a year ago

Instant.parse("2018-01-16T00:07:00.000+05:30") doesn't work, it throws java.time.format.DateTimeParseException

Laurent B Over a year ago

@Rahul edited as it worked with joda but java 8 Instant does not support timezones, you have to use OffsetDateTime

Anonymous Over a year ago

It’s preferred to use the Java 8 solution. Joda-Time is in maintenance mode, and SimpleDateFormat long outdated and notoriously troublesome. If using Java 6 or 7, consider adding ThreeTen Backport to your project so you can use the Java 8 solution.

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