Python: Convert String containing Multiple True / False / Parenthesis into a Boolean

Question

I'm wondering how, in Python, I could convert strings like:

"(True & False) | True"
"((False | False) & (True | False)) & (False | True)"

To a boolean answer:

True
False

The bool() function doesn't seem to work.

Thanks,

Cory Kramer · Accepted Answer · 2018-02-04 17:13:04Z

3

You can simply eval these expressions as they are valid Python

>>> eval("(True & False) | True")
True
>>> eval("((False | False) & (True | False)) & (False | True)")
False

answered Feb 4, 2018 at 17:13

Cory Kramer

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3 Comments

kingstante Over a year ago

Be careful with eval. It evaluates the expression before validity and should be used with caution: stackoverflow.com/questions/15197673/…

Jeremie Over a year ago

Thanks for the help @CoryKramer and @"Notice Me Senpai"!

Bill Bell Over a year ago

If you have any doubt that a string that you're offering to eval might have unwanted characters in it, in your case, you can use the following code: import re;s = "((False | False) & (True | False)) & (False | True)";if not re.sub(r'[\(\)\|&TrueFals ]*', '', s):eval(s). This strips out everything other than True, False, etc. If anything remains then the eval would not be executed.

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