I see that a Scala Array can be easily converted to List, Seq etc, using the s.toList or s.toSeq. Now, I would like to convert an array to a bufferarray. How would I do it?
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4 Answers
There's a generic method to that can convert between arbitrary collection types.
Array(1, 2, 3).to[ArrayBuffer]
Or from Scala 2.13 onwards:
Array(1, 2, 3).to(ArrayBuffer)
Comments
Use Iterable: _*:
val arr = Array(1,2,3)
arr: Array[Int] = Array(1, 2, 3)
val buf = collection.mutable.ArrayBuffer(arr: _*)
buf: scala.collection.mutable.ArrayBuffer[Int] = ArrayBuffer(1, 2, 3)
The _* means to unpack the Iterable elements. So arr: _* unpacks the elements of arr into a variable length list - which is an acceptable parameter list for `ArrayBuffer.
answered Feb 4, 2018 at 20:02
WestCoastProjects
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2 Comments
zell
Could you please explain the "_*" part?
WestCoastProjects
Represents the elements of the
Iterable . The underscore represents an individual element and the asterisk signifies: "now take all of them"please try Array(1, 2, 3).toBuffer
Comments
For anyone that is now looking for the answer, the answer which has been accepted is deprecated. If you will try to execute it then it will execute it successfully but will give you a warning message. So either you can refer Claire Hou answer or you can use
Array('a','b','c').toIndexedSequence
