I'm trying to figure out how to combine INSERT FROM SELECT and returning id value of inserted record.
INSERT INTO [someDB].[dbo].[OBJ] ( column1, column2, column3 )
OUTPUT inserted.ID (SELECT TOP 1 590675, column2, column3
FROM [someDB].[dbo].[OBJ] WHERE ID = 317817)
If you are trying to get the new ID after your INSERT statement you can use SCOPE_IDENTITY, IDENT_CURRENT or @@IDENTITY. For example:
INSERT INTO [someDB].[dbo].[OBJ] ( column1, column2, column3 )
SELECT TOP 1
590675,
column2,
column3
FROM [someDB].[dbo].[OBJ] WHERE ID = 317817
ORDER BY ...
SELECT SCOPE_IDENTITY(); -- Last identity generated in current session and current scope
SELECT @@IDENTITY; -- Last identity generated in current session across all scopes
SELECT IDENT_CURRENT([someDB].[dbo].[OBJ]) -- Last identity generated for the given table in any session and any scope
Because you are inserting just one row, SCOPE_IDENTIY() would be the best approach.
Hope it helps.
Your syntax is a little wrong here.
You want:
INSERT INTO [someDB].[dbo].[OBJ] ( column1, column2, column3 )
OUTPUT inserted.ID
SELECT TOP 1
590675,
column2,
column3
FROM [someDB].[dbo].[OBJ] WHERE ID = 317817
ORDER BY ...?; --You have a TOP 1, thus you really need an ORDER BY as well.
