Operator Overloading C++

Question

I found this code on internet :

Class Book{
Public:
void operator()(int Counter) const throw();
}

My question is, what operator overloading the above code used?

Overloading the parenthesis operator ()

user3046287
– user3046287

2015-12-31 21:50:46 +00:00
Commented Dec 31, 2015 at 21:50 — user3046287
– user3046287, Commented Dec 31, 2015 at 21:50

Marcelo Cantos · Accepted Answer · 2011-02-02 08:44:28Z

11

Firstly, that code is wrong; since C++ is case sensitive, Class and Public are not keywords. It is also very unusual (albeit legal) to capitalize the first letter of a parameter name (Counter).

Assuming correct capitalization, what you have is an overload of the function-call operator. It allows you to "call" an instance of Book as if it was a function:

Book b;
...
b(23);

answered Feb 2, 2011 at 8:44

Marcelo Cantos

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Comments

Arunmu · Accepted Answer · 2011-02-02 09:05:28Z

2

The above class is basically called a "Functor". It has an overloaded "()" operator. Widely used in STL Algorithms.

answered Feb 2, 2011 at 9:05

Arunmu

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