org.json.JSONException: "JSON object not found in JSON array"

Question

A very simple JSON like this (response.getBody().toString()):

{"per_page":50,"total":93,"last_page":2,"stars":[]}

Has some problems when I want to parse it:

JSONObject object = new JSONObject(response.getBody()); // no error
System.out.println(object.getJSONObject("total")); // not found

org.json.JSONException: JSONObject["total"] not found.

Other properties cannot be parsed either:

JSONArray startups = object.getJSONArray("stars");

org.json.JSONException: JSONObject["stars"] not found.

The key is to hold the value of response.getBody()

String json = response.getBody().toString();

The code snippets look Ok so there must be an error in the other parts of the code. — user8390068
– user8390068, Commented Feb 10, 2018 at 20:00
I would rather create model to map that response and read the values. — Yogen Rai
– Yogen Rai, Commented Feb 10, 2018 at 20:09

akhilesh0707 · Accepted Answer · 2018-02-10 20:18:33Z

3

Inside object total is not JSONObject it is an Int value, that's why you code crashing.

So use this

System.out.println(String.valueOf(object.getInt("total")));

instead of

System.out.println(object.getJSONObject("total"));

edited Feb 10, 2018 at 20:18

answered Feb 10, 2018 at 20:08

akhilesh0707

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4 Comments

Simon Berthiaume Over a year ago

Actually, because of the missing doublequotes, it might be a JsonNumber accessible using object.getJsonNumber("total"), but you are right about it not being an object.

Dylan Czenski Over a year ago

It is actually an int. I tried getInt(), getString() and get(), same result

akhilesh0707 Over a year ago

use System.out.println(object.getInt("total")+"")

akhilesh0707 Over a year ago

before getting the value from object check the value is present or not. using object.has("total")

jrtapsell · Accepted Answer · 2018-02-10 20:37:38Z

1

String json = "{\"per_page\":50,\"total\":93,\"last_page\":2,\"stars\":[]}":

JSONObject jsonObject = new JSONObject (json);

JSONArray jsonArray  = jsonObect.getJSONArray("stars");

int perPage = jsonObject.getInt("per_page");

try like this...

edited Feb 10, 2018 at 20:37

jrtapsell

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answered Feb 10, 2018 at 20:26

Ahamed Yasin Majeeth

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Comments

Yogen Rai · Accepted Answer · 2018-02-10 20:21:18Z

0

In addition to earlier answer, to parse array, use getJSONArray as

JSONArray ja = jsonObj.getJSONArray("stars");

You can loop-over the array as:

for(int j=0; j<ja.length(); j++) {
    JSONObject json = ja.getJSONObject(j);
    // do same as before for string, int or other data types
}

answered Feb 10, 2018 at 20:21

Yogen Rai

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