RegEx for URL validation - Javascript ( AngularJs )

Question

I need following URL should be returned as true

Following url should be returned as false

http://some.url/test?id=something
http://some.url/test?id=something&value=somethingelse
somerandomvalue

This is regex I tried so far /^(?:http(s)?:\/\/)?[\w.-]+(?:\.[\w\.-]+)+[\w\-\._~:/?#[\]@!\$&'\*\+,;=.]+$/. Im using this inside angular form input ng-patter

Any help would be appreciated

looks like you are categorizing get request data as false. Couldn't you just search for "?" — hvaminion
– hvaminion, Commented Feb 13, 2018 at 10:18
try this pattern maybe it'll fit you: /([a-z0-9_\-]{1,5}:\/\/)?(([a-z0-9_\-]{1,}):([a-z0-9_\-]{1,})\@)?((www\.)|([a-z0-9_\-]{1,}\.)+)?([a-z0-9_\-]{3,})(\.[a-z]{2,4})(\/([a-z0-9_\-]{1,}\/)+)?([a-z0-9_\-]{1,})?(\.[a-z]{2,})?(([\?\&][a-z0-9_\-]{1,}\=[a-z0-9_\-]{1,})+)?/gi — mathiasF
– mathiasF, Commented Feb 13, 2018 at 10:27

Arzoo · Accepted Answer · 2018-02-13 10:41:43Z

1

Try this regular expression

/^((?:http://)|(?:https://))(www.)?((?:[a-zA-Z0-9]+.[a-z]{3})|(?:\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}(?::\d+)?))([/a-zA-Z0-9.]*)$/gm

function isUrlValid(userInput) {
    var res = userInput.match(/^((?:http:\/\/)|(?:https:\/\/))(www.)?((?:[a-zA-Z0-9]+\.[a-z]{3})|(?:\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}(?::\d+)?))([\/a-zA-Z0-9\.]*)$/gm);
    if(res == null)
        return false;
    else
        return true;
 }

edited Feb 13, 2018 at 10:41

answered Feb 13, 2018 at 10:30

Arzoo

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1 Comment

Shafeeque Over a year ago

something is wrong with regex. it is throwing error

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