Unset Values from an Array that Match another Array

Question

What would be the quickest and most efficient way of ensuring that the values that match $config['a'] are not set in $config['b']?

In this case Sunday 14 should be unset from $config['b']['Hours']['Sunday']

$duplicates = array_intersect($config['a']['Hours'], $config['b']['Hours']);

Gives me an error, "Notice: Array to string conversion", and incorrect results, so either my array has been constructed incorrectly or my approach is incorrect.

Here is the array;

    $config  =  array(
                "a" => array(
                    "Hours" => array(
                        "Sunday" => array(12,13,14,15,16),
                    ),
                ),
                "b" => array(
                    "Hours" => array(
                        "Sunday" => array(0,1,2,3,4,5,6,7,8,9,10,11,14,17,18,19,20,21,22,23),
                        "Monday" => array(0,1,2,3,4,5,19,18,19,20,21,22,23),
                        "Tuesday" => array(0,1,2,3,4,5,19,18,19,20,21,22,23),
                        "Wednesday" => array(0,1,2,3,4,5,19,18,19,20,21,22,23),
                        "Thursday" => array(0,1,2,3,4,5,19,18,19,20,21,22,23),
                        "Friday" => array(0,1,2,3,4,5,19,18,19,20,21,22,23),
                        "Saturday" => array(0,1,2,3,4,5,8,19,20,21,22,23,24),
                    ),
                ),
            );

Jakub Krawczyk · Accepted Answer · 2018-02-14 18:09:27Z

2

array_intersect does not work recursively, as specified in the documentation: https://secure.php.net/array_intersect.

It iterates and compares values as strings, thus the error, because it tries to use value array(12,13,14,15,16) as string and fails.

The correct way in your case would be to compare keys first using array_keys(), then for the keys that exist use array_intersect() or array_diff().

Edit:

This example should work in the desired way:

$duplicateKeys = array_intersect(array_keys($config['a']['Hours']), array_keys($config['b']['Hours']));
$duplicates = [];

if(!empty($duplicateKeys) && is_array($duplicateKeys)) {
    foreach($duplicateKeys as $key) {
        $duplicates[$key] = array_intersect($config['a']['Hours'][$key], $config['b']['Hours'][$key]);
    }
}

edited Feb 14, 2018 at 18:09

answered Feb 14, 2018 at 18:03

Jakub Krawczyk

9708 silver badges16 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Stuart Over a year ago

Clever Sod! Works great, Thank you.

splash58 · Accepted Answer · 2018-02-14 19:46:18Z

0

To remove from array b values, presented in corresponding 'a', use array_diff function

foreach($config['a']["Hours"] as $k => $v) { 
      $config['b']["Hours"][$k] = array_diff( $config['b']["Hours"][$k], $v);
    }

answered Feb 14, 2018 at 19:46

splash58

26.2k3 gold badges25 silver badges35 bronze badges

2 Comments

sevavietl Over a year ago

Might be problematic if $config['b']["Hours"][$k] doesn't exist. Although, if the b array always contains all keys, it is not a problem.

splash58 Over a year ago

I guess that contains. I hope OP add a check if it'not so

Collectives™ on Stack Overflow

Unset Values from an Array that Match another Array

2 Answers 2

1 Comment

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related