I have a client class, in which it should connect to the server (in this case, iKettle) and sends and receives data. The IP address should come from another main server (so another class), and this IP address can change.
Below is the client code:
#command codes
_ON = "0x4<LF>"
_OFF = "0x0<LF>"
#base command
_BASE_COMMAND = "set sys output "
_SLEEP_TIME = 0.5
#size of buffer when receiving data
_BUFFER_SIZE = 1024
ip_address = ""
port = 2000
def initialiseSocket(self,ip_address):
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((ip_address, self.port))
return s
def setOn(self,ip_address):
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((ip_address, self.port))
s.send("set sys output 0x4<LF>")
time.sleep(self._SLEEP_TIME)
self.kettleResponse(ip_address)
def setOff(self,ip_address):
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((ip_address, self.port))
s.send(self._BASE_COMMAND + self._OFF)
time.sleep(self._SLEEP_TIME)
self.kettleResponse(ip_address)
def kettleResponse(self,ip_address):
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((ip_address, self.port))
data = s.recv(self._BUFFER_SIZE)
print(data)
And this is an example of commands from another class:
kettle.setOn(KETTLEIP)
However, when running this code, it does not print anything.
Can anyone help please?
kettle.setOn(KETTLEIP)seems like it should run untilprint(data), but you say there is no printout. Does the code get stuck somewhere?class Kettle: