skip a value in one dimension of numpy array

Question

I have a numpy array whose shape is (72, 671). Typically I select everything across the first dimension like this:

new_var = old_var[0:72]

However, for one file, I need to skip #18 across the first dimension. In other words, I want to select 0:17 and then 19:72 (or however you would write that correctly based on what is/isn't included). I have tried:

new_var=old_var[0:18,19:72]

but this only selects 0:18 in the first dimension and then 19:72 in the second. at least this is what I think it's doing, since the length of the resulting variable is 18. I can't find how to correct the syntax, so any help would be appreciated.

Scott Boston · Accepted Answer · 2018-02-20 18:14:28Z

3

I think you can use np.r_

old_var = np.random.random((72,671))
new_var = old_var[np.r_[0:18,19:72]]
new_var.shape

Output:

(71, 671)

answered Feb 20, 2018 at 18:14

Scott Boston

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llllllllll · Accepted Answer · 2018-02-20 18:18:01Z

2

You can use fancy indexing:

a[list(range(18)) + list(range(19, 72))]

Or np.vstack:

np.vstack((a[:18], a[19:]))

answered Feb 20, 2018 at 18:18

llllllllll

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