how would I sort this using .sort() function in javascript? I know I can add a comparison function here but I'm not sure how I would program this.
Before
1 024c
100 000c
143c
1 020c
10 000c
After
143c
1 020c
1 024c
10 000c
100 000c
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2What is format in which you are getting this input? On what basis are you sorting this? What have you tried?void– void2018-02-21 18:24:58 +00:00Commented Feb 21, 2018 at 18:24
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1Can you show your first implementation.amar_1995– amar_19952018-02-21 18:26:54 +00:00Commented Feb 21, 2018 at 18:26
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@void I am trying to order a table column which text similar to this. I have tried the very basic return a-b which works for columns which only has textuser7254823– user72548232018-02-21 18:32:32 +00:00Commented Feb 21, 2018 at 18:32
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@confusedOne see my answer below.void– void2018-02-21 18:33:05 +00:00Commented Feb 21, 2018 at 18:33
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2 Answers
If your input is an array then you can use a comparator function
(a,b) => a.replace(/[^\d.]/g, "") - b.replace(/[^\d.]/g, "")
this will remove c and space from the string to form number and compare. See the code below.
var data = ["1 024c",
"100 000c",
"143c",
"1 020c",
"10 000c"]
var sorted = data.sort( (a,b) => a.replace(/[^\d.]/g, "") - b.replace(/[^\d.]/g, ""));
console.log(sorted);2 Comments
Scott Sauyet
This looks good, but you might want to replace
/ |c/g with either /\D/g or /[^\d.]/g. The first one keeps only digits. The second keeps only digits and decimals.
void
@ScottSauyet makes sense. Edited :)
It seems like you want to sort it based on the numbers in them, while excluding spaces.
x.sort(
(eachObj, prevObj) =>
parseInt(eachObj.replace(" ","")) - parseInt(prevObj.replace(" ",""))
);
In ES6
2 Comments
Scott Sauyet
Note that this gives back
["143c", "1020c", "1024c", "10000c", "100000c"], which is not what's wanted. You need to retain the spaces after sort.
hashedram
@ScottSauyet missed that. Edited. Thx.