TypeError: 'int' object is not iterable after using sorted function (python 2.7)

Question

So I'm writing this code to see if an element in a list could be removed to make the list increasing. in the code below why do I get this error?

def almostIncreasingSequence(sequence):
    sorted_sequence = sorted(sequence)
    counter = 0
    for i in len(sequence):
        if sorted_sequence[i] != sequence[i]:
            counter += 1
    if counter > 1:
        return True
    else:
        return False

Look again at for i in len(sequence). len(sequence) is a number. You probably mean range(len(sequence)). — Warren Weckesser
– Warren Weckesser, Commented Feb 23, 2018 at 2:04

wim · Accepted Answer · 2018-02-23 02:05:38Z

1

len(sequence) is a number here, and you can't iterate a number:

for i in len(sequence):
    ...

You probably wanted

for a,b in zip(sequence, sorted_sequence):
    ...

You may as well return the count rather than a boolean, or return from within the for-loop, since it's not necessary to iterate the entire sequence to check whether this count is > 1.

answered Feb 23, 2018 at 2:05

wim

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